我有四个select语句,我想将它们全部加入以获取公共行。
在一个例子中,我提供了2个选择语句:
SELECT
h.userid, 'Activity' as table_name,
h.stamp,
DATEDIFF(dd, kh.LatestDate, GETDATE()) as days_since,
m.group_name
FROM
([Animal].[SYSADM].[activity_history] h
INNER JOIN
(SELECT userid, MAX(stamp) as LatestDate
FROM [Animal].[SYSADM].[activity_history]
GROUP BY userid) kh ON h.userid = kh.userid AND h.stamp = kh.LatestDate)
LEFT OUTER JOIN
[Animal].[SYSADM].secure_member m ON m.user_name = h.userid
WHERE
(DATEDIFF(dd, kh.LatestDate, GETDATE()) > 90)
AND NOT (m.group_name = 'inactive')
ORDER BY
userid
SELECT
h.userid, 'Person' as table_name, h.stamp,
DATEDIFF(dd, kh.LatestDate, GETDATE()) as days_since,
m.group_name
FROM
([Animal].[SYSADM].[person_history] h
INNER JOIN
(SELECT userid, max(stamp) as LatestDate
FROM [Animal].[SYSADM].[person_history]
GROUP BY userid) kh ON h.userid = kh.userid AND h.stamp = kh.LatestDate)
LEFT OUTER JOIN
[Animal].[SYSADM].secure_member m ON m.user_name = h.userid
WHERE
(DATEDIFF(dd, kh.LatestDate, GETDATE()) > 90)
AND NOT (m.group_name = 'inactive')
ORDER BY
userid
我已经尝试了INTERSECT
,但它没有返回任何行,我想看到两个select语句中的常见行(实际上我有4个所以我相信适用于2的行将适用于4)
提前致谢。
更新
我在2个select语句中尝试了内连接,它给了我想要的结果,但现在的问题是如何在4个select语句中使用内连接。
SELECT DISTINCT t1.userid as A_UserID, t2.userid as P_UserID, t1.stamp as A_stamp, t2.stamp as P_stamp, datediff(dd,t1.stamp,GetDate()) as A_days_since, datediff(dd,t2.stamp,GetDate()) as P_days_since, t1.group_name, t1.table_name, t2.table_name
from
(SELECT h.userid, 'Activity' as table_name, h.stamp, datediff(dd,kh.LatestDate,GetDate()) as days_since, m.group_name
FROM
( [Animal].[SYSADM].[activity_history] h
inner join (
select userid, max(stamp) as LatestDate
from [Animal].[SYSADM].[activity_history]
group by userid
) kh on h.userid = kh.userid and h.stamp = kh.LatestDate
)
left outer join [Animal].[SYSADM].secure_member m on m.user_name = h.userid
where
(datediff(dd,kh.LatestDate, GetDate()) > 90)
and not (m.group_name = 'inactive')) t1
inner join
(SELECT h.userid, 'Person' as table_name, h.stamp, datediff(dd,kh.LatestDate,GetDate()) as days_since, m.group_name
FROM
( [Animal].[SYSADM].[person_history] h
inner join (
select userid, max(stamp) as LatestDate
from [Animal].[SYSADM].[person_history]
group by userid
) kh on h.userid = kh.userid and h.stamp = kh.LatestDate
)
left outer join [Animal].[SYSADM].secure_member m on m.user_name = h.userid
where
(datediff(dd,kh.LatestDate, GetDate()) > 90)
and not (m.group_name = 'inactive')) t2
on
t1.userid = t2.userid
order by T1.userid
答案 0 :(得分:1)
暂时忘掉UNION
。想象一下,您将结果插入Table1
然后依赖你的意思"常见的行"。如果你想要精确的值,但在不同的表中
SELECT userid, h.stamp, days_since, m.group_name
FROM Table1
GROUP BY userid, h.stamp, days_since, m.group_name
HAVING COUNT( table_name ) = 2 -- in this case 2 because are two types
-- Activity and Persons
查看查询结果后,您还需要为DISTINCT
上的每个查询添加UNION
。