select distinct
x.vrgid, x.Weights, x.geom
from
(select
-- postcodes.id as postcodeid ,,fishnet.geom as geom
fishnet.gid as vrgid,
fishnet.geom as geom,
CASE WHEN
st_intersects(centroids.geom, urban.geom) and counts.nonurbancells != 0
THEN 0.95 :: numeric / counts.urbancells -------1st case
WHEN st_intersects(centroids.geom, urban.geom) and counts.nonurbancells = 0
THEN 1.00 :: numeric / counts.urbancells ---2ndcase
WHEN Not st_intersects(centroids.geom, urban.geom) = fishnet.gid :: boolean and counts.nonurbancells != 0
THEN 0.05 :: numeric / counts.nonurbancells ----3rd case
ELSE 0
END AS Weights
from vrg.urban_nonurban_count_new as counts
inner join vrg.gfk_2016_id_5_digit_pcd_areas2013_projected as postcodes on postcodes.id = counts.postid
right outer join vrg.rdsid_86_quadgrid_centroids as centroids on st_contains(postcodes.geom, centroids.geom)
left outer join vrg.rdsid86_quadgrid AS fishnet on fishnet.gid = centroids.gid
right outer join vrg.rdsid86_katrisk_poly_projected as urban on st_intersects(urban.geom, fishnet.geom)
where postcodes.id = '42395') as x
我的PL / Pgsql函数中有几个case语句,其中我得到重复的行(带有重复的vrgids)。以下是查询结果
这里(标记的行)id为7192是第一种情况声明的结果(参考查询) 我想要做的是使用循环或if条件从第一个case语句为真后从结果中删除vrgid和相应的权重。 所以我不会得到重复的记录。怎么可能?
可能是我应该在第3个语句中使用条件来得出第1个案例语句中没有的vrgids。