ObjectOutputStream重复输出

时间:2018-05-28 06:07:25

标签: java serializable objectoutputstream

在这种情况下甚至无法找到问题本身。当程序从 objects.dat 读取时,输出只是数组中最后一个对象的变量。 Program output screenshot. 我已经多次梳理了代码并找不到问题。据我所知,一切顺利,直到它尝试序列化并将对象写入/读取对象。#34;。如果有人能给我一个关于问题是什么或如何修复它的提示,我会非常感激。我认为问题可能出在readFile或writeFile方法中,但我无法确定。

目标是创建一个对象数组,将其序列化,将其写入文件,然后读取该文件。

public class Test implements Serializable{

public static void main(String[] args) throws InvalidTestScore, ClassNotFoundException, IOException {
    Scanner keyboard = new Scanner(System.in);
    int userInput;
    final int ARRAYLENGTH;
    //get info for ARRAYLENGTH and make a TestScore array.
    System.out.println("How many test scores are you finding the average of? (ex. 6 tests): ");
    ARRAYLENGTH = keyboard.nextInt();
    TestScores[] scoreArray = new TestScores[ARRAYLENGTH];
    //populate scoreArray with TestScore objects.
    for (int counter = 0; counter < scoreArray.length; counter++)
    {
       System.out.println("Enter the score of test " + (counter + 1) + ": ");
       userInput = keyboard.nextInt();
       scoreArray[counter] = new TestScores(counter, userInput);

    }

    System.out.println("Now writing the object to 'objects.dat'...");
    TestScores.writeFile(scoreArray);

    System.out.println("Now reading the object from 'objects.dat'...");
    TestScores.readFile(ARRAYLENGTH);
}



 package scoresPackage;
import java.io.*;

public class TestScores implements Serializable {

    static TestScores[] scoreArray, scoreRead;
    static int score, name;

    TestScores (int test, int num) throws InvalidTestScore
    {
        name = test;
        score = num;

        if (num >= 100 || num <= 0)
           {
              throw new InvalidTestScore();
           }
    }
    public static void writeFile(TestScores[] test) throws IOException
    {
        FileOutputStream outStream = new FileOutputStream("objects.dat");
        try (ObjectOutputStream objectOut = new ObjectOutputStream(outStream)) {
            for (int counter = 0; counter < test.length; counter++)
            {
                objectOut.writeObject(test[counter]);
                objectOut.reset();
            }
        }
        System.out.println("Writing success.");
    }
    public static void readFile(int ALENGTH) throws IOException, ClassNotFoundException
    {
        FileInputStream inStream = new FileInputStream("objects.dat");
        try (ObjectInputStream objectIn = new ObjectInputStream(inStream)) {
            scoreRead = new TestScores[ALENGTH];

            for (int counter = 0; counter < ALENGTH; counter++)
            {
                scoreRead[counter] = (TestScores) objectIn.readObject();
                System.out.println("Test " + name + " Score: " + score);

            }
        }
        System.out.println("Reading success.");

    }

1 个答案:

答案 0 :(得分:3)

这是问题所在:

static int score, name;

它与ObjectOutputStream无关 - 这意味着您不会为TestScores的每个实例分配一个分数和一个名称,但只有一个{{ 1}}变量和一个score 整体。您的name构造函数会覆盖这些变量,因此,当您创建第二个实例时,您已经丢失了您要求的第一个TestScores / name数据用户。一个很好的方法是完全删除scoreObjectOutputStream代码:一旦您向用户询问了所有信息,如果您尝试将其全部打印出来,会发生什么控制台? (您将看到相同的行为,基本上:您只会看到输入的最后一个值。)

您想要实例字段,而不是静态字段:

ObjectInputStream

(或者更好的是,将它们设为私有......这不是我对代码所做的唯一改变,但它是一个起点。)

有关静态字段与实例字段之间差异的更多详细信息,请参阅Java tutorial