Question

在以下程序中，我将输出作为Hibernate.UserDetails@224b4d61

我该如何解决这个问题？

以下是我正在使用的两个程序，我需要打印username

HibernateTest：

public class HibernateTest {
    public static void main(String[] args) 
    {
        SessionFactory sessionfactory = new Configuration().configure("Hibernate/hibernate.cfg.xml").buildSessionFactory();
        Session session = sessionfactory.openSession();
        session.beginTransaction();

        Criteria criteria = session.createCriteria(UserDetails.class);
        criteria.add(Restrictions.eq("UserName","User5"));
        List<UserDetails> user =(List<UserDetails>) criteria.list();
        session.getTransaction().commit();
        session.close();
        for(UserDetails u : user)
        {
            System.out.println("Name of User is : "+u);
        }
    }
}

的UserDetails：

@Entity
public class UserDetails 
{
    @Id @GeneratedValue(strategy=GenerationType.AUTO) 
    private int UserId;
    private String UserName;

    public int getUserId() {
        return UserId;
    }
    public void setUserId(int userId) {
        UserId = userId;
    }
    public String getUserName() {
        return UserName;
    }
    public void setUserName(String userName) {
        UserName = userName;
    }
}

Answer 1

您目前正在尝试打印整个UserDetails对象，但我认为您只是尝试打印用户名...

System.out.println("Name of User is : " + u.getUserName());

Answer 2

您应该覆盖toString method。

@Entity
public class UserDetails 
{
    @Id @GeneratedValue(strategy=GenerationType.AUTO) 
    private int UserId;
    private String UserName;

    public int getUserId() {
        return UserId;
    }
    public void setUserId(int userId) {
        UserId = userId;
    }
    public String getUserName() {
        return UserName;
    }
    public void setUserName(String userName) {
        UserName = userName;
    }

    public String toString() {
      return getUserName() + " (id = " + getUserId().toString()  + ")"
}

将输出作为对象而不是字符串

2 个答案: