Question

我正在尝试创建一个用于计算考试笔记的应用程序当我按下计算并且没有任何小数时，它会显示答案，但如果有小数则会崩溃

public class MainActivity extends AppCompatActivity {

    TextView Result;
    EditText Number1 , Number2, Number3, Number4, Number5, Number6;
    Button Calculate;

    float result_num;
    int num1,num2,num3,num4,num5,num6;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        Result = (TextView)findViewById(R.id.Result);

        Number1 = (EditText)findViewById(R.id.Number1);
        Number2 = (EditText)findViewById(R.id.Number2);
        Number3 = (EditText)findViewById(R.id.Number3);
        Number4 = (EditText)findViewById(R.id.Number4);
        Number5 = (EditText)findViewById(R.id.Number5);
        Number6 = (EditText)findViewById(R.id.Number6);

        Calculate = (Button)findViewById(R.id.Calculate);

        Calculate.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {

                num1 = Integer.parseInt(Number1.getText().toString());
                num2 = Integer.parseInt(Number2.getText().toString());
                num3 = Integer.parseInt(Number3.getText().toString());
                num4 = Integer.parseInt(Number4.getText().toString());
                num5 = Integer.parseInt(Number5.getText().toString());
                num6 = Integer.parseInt(Number6.getText().toString());

                result_num = ((((num1 + num2 + num3 + num4) / 4) * 20) / 100) + ((((num5 + num6) / 2) * 80) / 100);
                Result.setText(String.valueOf(result_num));

            }
        });
    }
}

Answer 1

基本上，您尝试将Double或Float值解析为Integer类型，代码如下：

Integer.parseInt(Number1.getText().toString());

您的代码不适用于十进制值。但是您可以将其更改为Double值，如下所示：

double value1 = Double.parseDouble(Number1.getText().toString());

Answer 2

使用Float而不是Integer。整数无法解析（并操作）带小数点的数字。

补充：这是错误检查代码：

try {
  num1 = Double.parseDouble(Number1.getText().toString());
  num2 = Double.parseDouble(Number2.getText().toString());
  ...
}
catch (NumberFormatException ex) {
  Toast.makeText(this, "Error: " + ex.getMessage(), Toast.LENGTH_LONG).show();
}

计算器崩溃

2 个答案: