Codable CoreData模型崩溃了`无法识别的选择器发送到实例`

时间:2018-05-27 14:35:06

标签: swift core-data unrecognized-selector codable

所以,我正在努力使我的模型类符合 NSManagedObject (对于CoreData持久性)和 Codable (对于JSON序列化/反序列化)。现在我的JSON解码器在反序列化之前得到了大约一半的错误

Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[Land setGun:]: unrecognized selector sent to instance 0x60400028f780'

我一直在遵循指南,以确保符合这里发现的两种模型协议How to use swift 4 Codable in Core Data?并且我意识到错误被抛出,因为(如果错误是可信的)Land类没有' setGun'方法。令我难以置信的是

A)当我解码Land类JSON时它没有发生错误(它处理没有问题),要击中的最后一个断点实际上是在Sea类的JSON解码器中。

B)Land类有一个'setGun'方法(我在类中声明了一个占位符方法,以确保它与自动生成的CoreData代码有关)。

我的Land类代码如下:

import Foundation
import CoreData
@objc(Land)
class Land : NSManagedObject, Equipment {
var type = EquipmentType.LAND

enum CodingKeys: String, CodingKey {
    case id
    case name
    case desc = "description"
    case groupIconUrl
    case individualIconUrl
    case photoUrl
    case primaryWeapon
    case secondaryWeapon
    case atgm
    case armor
    case speed
    case auto
    case weight
}

required convenience init(from decoder: Decoder) throws {
    guard let context = decoder.userInfo[CodingUserInfoKey.context!] as? NSManagedObjectContext else { fatalError() }
    guard let entity = NSEntityDescription.entity(forEntityName: "Land", in: context) else { fatalError() }
    self.init(entity: entity, insertInto: context)
    let container = try! decoder.container(keyedBy: CodingKeys.self)
    self.id = try container.decode(Int64.self, forKey: .id)
    self.name = try container.decodeIfPresent(String.self, forKey: .name)
    self.desc = try container.decodeIfPresent(String.self, forKey: .desc)
    self.groupIconUrl = try container.decodeIfPresent(String.self, forKey: .groupIconUrl)
    self.individualIconUrl = try container.decodeIfPresent(String.self, forKey: .individualIconUrl)
    self.photoUrl = try container.decodeIfPresent(String.self, forKey: .photoUrl)
    self.primaryWeapon = try container.decodeIfPresent(Gun.self, forKey: .primaryWeapon)
    self.secondaryWeapon = try container.decodeIfPresent(Gun.self, forKey: .secondaryWeapon)
    self.atgm = try container.decodeIfPresent(Gun.self, forKey: .atgm)
    self.armor = try container.decode(Int64.self, forKey: .armor)
    self.speed = try container.decode(Int64.self, forKey: .speed)
    self.auto = try container.decode(Int64.self, forKey: .auto)
    self.weight = try container.decode(Int64.self, forKey: .weight)
}
public func encode(to encoder: Encoder) throws {
    var container = encoder.container(keyedBy: CodingKeys.self)
    try container.encode(id, forKey: .id)
    try container.encode(name, forKey: .name)
    try container.encode(desc, forKey: .desc)
    try container.encode(groupIconUrl, forKey: .groupIconUrl)
    try container.encode(individualIconUrl, forKey: .individualIconUrl)
    try container.encode(photoUrl, forKey: .photoUrl)
    try container.encode(primaryWeapon, forKey: .primaryWeapon)
    try container.encode(secondaryWeapon, forKey: .secondaryWeapon)
    try container.encode(atgm, forKey: .atgm)
    try container.encode(armor, forKey: .armor)
    try container.encode(speed, forKey: .speed)
    try container.encode(auto, forKey: .auto)
    try container.encode(weight, forKey: .weight)
}
public func setGun(gun: Gun){}
}

我的CoreData dataModel也是屏幕上限:

CoreData dataModel

最后,如果所有这些都不足以诊断出现了什么问题,那么您可以自由克隆存储库并从以下公共github存储库本地运行它:https://github.com/jamesjmtaylor/weg-ios

1 个答案:

答案 0 :(得分:1)

您在Air.swift文件中的问题 我真的不知道为什么不解码Gun at Air文件解码器

self.gun = try container.decodeIfPresent(Gun.self, forKey: .gun)
self.agm = try container.decodeIfPresent(Gun.self, forKey: .agm)
self.aam = try container.decodeIfPresent(Gun.self, forKey: .aam)
self.asm = try container.decodeIfPresent(Gun.self, forKey: .asm)