应用程序在执行showStudents（）函数时崩溃

Question

#include <stdio.h>


    int count = 0;//global


struct student{

    char name[20];
    char surname[20];
    int age;
    char registrationDate[10];      
} v[200];





void addStudents(){


    printf("\nJu po shtoni nje student te ri ne liste!\n");

    printf("\nShkruani emrin:");
    scanf("%s", &v[count].name);

    printf("\nShkruani mbiemrin:");
    scanf("%s", &v[count].surname);

    printf("\nShkruani daten e regjistrimit:");
    scanf("%s", &v[count].registrationDate);

    printf("\nShkruani moshen:");
    scanf("%d", &v[count].age);

    printf("\nRegjistrimi u ruajt me sukses.\n");
    count ++;
    return;


}


void menu (){



        printf("\nShtyp 1 per te shtuar student.");
        printf("\nShtyp 2 per te shfaqur studentet.");
        printf("\nShtyp 3 per menune.");
        printf("\nShtyp 0 per te mbyllur programin.");

        return;
}

void showStudents(){


    int i = 0;
    for(i=0; i<=count; i++){
        printf("Emri i studentit te: %d: %s\n", i+1, v[i].name);

        printf("Mbiemri i studentit te: %d: %s\n", i+1, v[i].surname);

        printf("Data e regjistrimit i studentit te: %d: %s\n", i+1, v[i].registrationDate);

        printf("Mosha i studentit te: %d: %s\n", i+1, v[i].age);


    }

    return;
}


main(){ 

    printf("*******************PROGRAM PER LIBRARI NE GJUHEN C***********************\n\n");

    menu();
        bool cond = true;

        while(cond){

        int choice;
            printf("\n\nShkruani zgjedhjen tuaj: ");
            scanf("%d", &choice);

        switch(choice){
            case 1:
                addStudents();
            break;

            case 2:
                showStudents();
            break;

            case 3:
                menu();
            break;
            case 0:
                cond = false;

        }


    }

}

我只是不知道它为什么会一直崩溃。它打印出第一个学生数据而不是崩溃。因此，如果我添加超过1名学生，它将打印出第一个数据，而不会因为崩溃而打印出其他数据。我正在为学生添加addStudents（）函数并使用showStudent（）打印他们的数据。任何sugesstion？