您好我有一个数据框如下:
并且想要创建一个包含2列的数据框:
Writer1 Writer2
列出了歌曲作者的所有排列:对于歌曲03 Bonnie&作家克莱德:Prince,Tupac Shakur,Jay-Z,Tyrone Wrice和Kanye West参与其中。因此,我的数据框应如下所示:
Writer1 Writer2
Prince Tupac Shakur
Prince Jay-Z
Prince Tyrone Wrice
Prince Kanye West
Tupac S Jay-Z
Tupac S Tyrone Wrice
Tupac S Kanye West
Jay-Z Tyrone Wrice
Jay-Z Kanye West
Tyrone Kanye West
我知道如何解决这个问题吗?
答案 0 :(得分:0)
以下是使用itertools.combinations
的一种方法:
import itertools
import pandas as pd
def get_combinations(df, song_name):
"""
Get a dataframe of all two-writer combinations for a given song.
:param df: dataframe containing all artists, songs and writers
:param song_name: name of song
:returns: dataframe with cols 'Writer1', 'Writer2' of all two writer combinations for the given song
"""
song_frame = df[df['Song'] == song_name]
combinations_df = pd.DataFrame(list(itertools.combinations(song_frame['Writer'].unique(), 2)),
columns=['Writer1', 'Writer2'])
return combinations_df
combinations_df = get_combinations(df, '03 Bonnie & Clyde')
请注意,这假设您的数据采用Pandas数据帧的形式。您可以轻松地从文本文件或csv中读取,或者创建类似以下内容的文件来测试:
import numpy as np
df = pd.DataFrame({'Artist':np.repeat('Jay-Z',5).tolist() + ['David Bowie'] * 2 + ['List of the X Factor finalists] * 2,
'Song':np.repeat('03 Bonnie & Clyde',5).tolist() + ['Heroes'] * 4,
'Writer':['Prince', 'Tupac Shakur',
'Jaz-Z', 'Tyrone Wrice',
'Kanye West'] + ['David Bowie', 'Brian Eno'] * 2})
如果您想在整个数据框架中有效地应用此功能,请考虑:
def combinations_per_group(group):
"""Return combinations of writers after grouping by song."""
group_combs = pd.DataFrame(list(itertools.combinations(group['Writer'].unique(),2)),
columns=['Writer1', 'Writer2'])
combinations_df = df.groupby(['Song']).apply(combinations_per_group)\
.reset_index()\
.drop('level_1', axis=1)
这将返回一个数据帧,其中歌曲作为索引,所需的列给出了每首歌曲的所有作者组合。