我一直在使用Google语音识别功能。这是我的代码:
import speech_recognition as sr
r = sr.Recognizer()
with sr.Microphone() as source:
print("Say something!")
audio = r.listen(source)
print(r.recognize_google(audio))
尽管识别非常准确,但在吐出识别出来的文本之前大约需要4-5秒。由于我正在创建一个语音助手,我想修改上面的代码,以使语音识别更快。
我们有什么方法可以将这个数字降低到1-2秒左右?如果可能的话,我试图像Siri和Ok Google这样的服务一样快速地进行识别。
我是python的新手,所以如果对我的问题有一个简单的答案我很抱歉。
答案 0 :(得分:2)
您可以使用其他语音识别程序。例如,您可以在IBM设置一个帐户以使用其Watson Speech To Text。 如有可能,请尝试使用其websocket界面,因为这样,当您仍在讲话时,它将主动记录您的发言。
一个示例(不使用websockets)将是:
import speech_recognition as sr
# obtain audio from the microphone
r = sr.Recognizer()
with sr.Microphone() as source:
print("Adjusting for background noise. One second")
r.adjust_for_ambient_noise(source)
print("Say something!")
audio = r.listen(source)
IBM_USERNAME = "INSERT IBM SPEECH TO TEXT USERNAME HERE" # IBM Speech to Text usernames are strings of the form XXXXXXXX-XXXX-XXXX-XXXX-XXXXXXXXXXXX
IBM_PASSWORD = "INSERT IBM SPEECH TO TEXT PASSWORD HERE" # IBM Speech to Text passwords are mixed-case alphanumeric strings
try:
print("IBM Speech to Text thinks you said " + r.recognize_ibm(audio, username=IBM_USERNAME, password=IBM_PASSWORD))
except sr.UnknownValueError:
print("IBM Speech to Text could not understand audio")
except sr.RequestError as e:
print("Could not request results from IBM Speech to Text service; {0}".format(e))
您也可以尝试使用Pocketsphinx,但就我个人而言,我并没有特别好的经验。它是离线的(加号),但是对我而言并不是特别准确。您可能需要调整一些检测设置并消除一些背景噪音。我相信,还有一种训练方法可以将其修改为您的声音,但看起来并不简单。
一些有用的链接:
Microphone recognition example
祝你好运。一旦语音识别正常工作,它就会非常有用且有益!
答案 1 :(得分:-1)
def speech_to_text():
required=-1
for index, name in enumerate(sr.Microphone.list_microphone_names()):
if "pulse" in name:
required= index
r = sr.Recognizer()
with sr.Microphone(device_index=required) as source:
r.adjust_for_ambient_noise(source)
print("Say something!")
audio = r.listen(source, phrase_time_limit=4)
try:
input = r.recognize_google(audio)
print("You said: " + input)
return str(input)
except sr.UnknownValueError:
print("Google Speech Recognition could not understand audio")
except sr.RequestError as e:
print("Could not request results from Google Speech Recognition service; {0}".format(e))