Question

我有点谜题。我有所有奖项的数组1

array1 = [
  {
    "finished": 1,
    "awardName": "The beginning",
    "description": "Complete one excersise",
    "difficulty": "easy",
    "awarded": false
  },
  {
    "finished": 5,
    "awardName": "Five of a kind",
    "description": "Complete five excersises",
    "difficulty": "medium",
    "awarded": false
  }, ... ]`

和获奖的阵列2。

[
  {
    "award": "Five of a kind"
  },
  {
    "award": "The beginning"
  },
  {
    "award": "firstTimeLogin"
  }
]

我想要做的是比较两个数组中的awardNames，如果有同名的奖励，请将对象awarded更改为true。它看起来应该是这样的，this.array1[indexOfSecondArrayContainingThatAwardname].awarded = true。我希望这是可能的，因为我还没有javascript的问题。谢谢！

Answer 1

尝试使用findIndex()：

＆＃13;

const array1 = [{
    "finished": 1,
    "awardName": "The beginning",
    "description": "Complete one excersise",
    "difficulty": "easy",
    "awarded": false
  },
  {
    "finished": 5,
    "awardName": "Five of a kind",
    "description": "Complete five excersises",
    "difficulty": "medium",
    "awarded": false
  }
];

const array2 = [{
    "award": "Five of a kind"
  },
  {
    "award": "The beginning"
  },
  {
    "award": "firstTimeLogin"
  }
];

for (const { award } of array2) {
  const idx = array1.findIndex(i => i.awardName === award);
  if (idx !== -1) 
    array1[idx].awarded = true;
}

console.log(array1);

＆＃13;

Answer 2

与forEach和map一起使用。

＆＃13;

let array1 = [{
    "finished": 1,
    "awardName": "The beginning",
    "description": "Complete one excersise",
    "difficulty": "easy",
    "awarded": false
  },
  {
    "finished": 5,
    "awardName": "Five of a kind",
    "description": "Complete five excersises",
    "difficulty": "medium",
    "awarded": false
  }
]

const array2 = [{
    "award": "Five of a kind"
  },
  {
    "award": "The beginning"
  },
  {
    "award": "firstTimeLogin"
  }
]

array2.forEach(award2=>{
  array1 = array1.map(award1=>{
    if(award2.award === award1.awardName){
      award1.awarded = true;
    }
    return award1;
  })
});

console.log(array1);

＆＃13;

Answer 3

您可以使用map和filter来链接抛出数组并返回所需的结果

＆＃13;

var array1 = [
  {
    "finished": 1,
    "awardName": "The beginning",
    "description": "Complete one excersise",
    "difficulty": "easy",
    "awarded": false
  },
  {
    "finished": 5,
    "awardName": "Five of a kind",
    "description": "Complete five excersises",
    "difficulty": "medium",
    "awarded": false
  }
]
  

var array2 = [
  {
    "award": "Five of a kind"
  },
  {
    "award": "The beginning"
  },
  {
    "award": "firstTimeLogin"
  }
]

array1.map(ele =>{
  if (array2.filter(ele2 => ele.awardName === ele2.award).length > 0) ele.awarded = true;           
});

console.log(array1);

＆＃13;

Answer 4

您可以使用哈希表并使用array2进行设置，并使用array1``进行检查。

var array1 = [{ finished: 1, awardName: "The beginning", description: "Complete one excersise", difficulty: "easy", awarded: false }, { finished: 5, awardName: "Five of a kind", description: "Complete five excersises", difficulty: "medium", awarded: false }],
    array2 = [{ award: "Five of a kind" }, { award: "The beginning" }, { award: "firstTimeLogin" }],
    map = Object.create(null);
  
array2.forEach(({ award }) => map[award] = true);

array1.forEach(o => map[o.awardName] && (o.awarded = true));

console.log(array1);

在数组中查找项目并推送到其他数组

4 个答案: