我有以下查询:
MATCH (dg:DecisionGroup)-[:CONTAINS]->(childD:Decision)
WHERE dg.id = {decisionGroupId}
MATCH (filterCharacteristic1:Characteristic)
WHERE filterCharacteristic1.id = 1
WITH dg, filterCharacteristic1
CALL apoc.index.between(childD,'HAS_VALUE_ON',filterCharacteristic1,'(value:(10))') YIELD rel
WITH DISTINCT rel, childD, dg
MATCH (childD)-(rel) // here I need to go further only with 'childD' nodes that have relationship with 'rel'(match `apoc.index.between` predicate)
正如您从上面的查询中看到的那样 - 最后我尝试过滤与childD
有关系的rel
个节点,但我不知道如何描述它在Cypher。像(childD)-(rel)
或(childD)-[rel]
之类的东西不起作用并导致错误。请帮忙
答案 0 :(得分:1)
您需要查找匹配模式并比较关系:
...
WITH DISTINCT rel, childD, dg, startNode(rel) AS sRel, endNode(rel) AS eRel
WHERE (childD)--(sRel) OR (childD)--(eRel)
RETURN rel, child, dg
或者你可以直接比较:
alternatingSums = a => a.reduce((accum,value,i) => (accum[i&1] += value, accum), [0,0])