我要做的就是在一系列细胞中加1,直到它到达空白细胞。我还从另一个细胞范围减1,直到它到达空白细胞。我目前单独编码每个单元格,但数据变化的单元格数量并不实用。
以下是我编写的代码摘录,任何人都可以帮助我吗?
function Calculations() {
//Week Number & Week Pay
var spreadsheet = SpreadsheetApp.getActiveSpreadsheet()
s=SpreadsheetApp.setActiveSheet(spreadsheet.getSheetByName("Money")
var currVal=s.getRange("C2").getValue()
var plusVal= currVal +1
s.getRange("C2") .setValue(plusVal)
var currVal=s.getRange("B2").getValue()
var minusVal= currVal -1
s.getRange("B2") .setValue(minusVal)
var currVal=s.getRange("C3").getValue()
var plusVal= currVal +1
s.getRange("C3") .setValue(plusVal)
var currVal=s.getRange("B3").getValue()
var minusVal= currVal -1
s.getRange("B3") .setValue(minusVal)
var currVal=s.getRange("C4").getValue()
var plusVal= currVal +1
s.getRange("C4") .setValue(plusVal)
var currVal=s.getRange("B4").getValue()
var minusVal= currVal -1
s.getRange("B4") .setValue(minusVal)
}
答案 0 :(得分:0)
我没有使用A1或R1C1表示法,而是在获取单元格位置(范围)时更容易使用数字。
增加循环结束时的行号。循环将使用数据迭代最大行数,如果找到空单元格,它将中断。
function Calculations() {
try{
//Week Number & Week Pay
var currVal,i,L,lastRow,minusVal,plusVal,ss,sh,theColumn,theRng,theRow;
ss = SpreadsheetApp.getActiveSpreadsheet();//Get the active spreadsheet
sh = ss.getSheetByName("Money");//Get a sheet tab by name
lastRow = sh.getLastRow();//Get the number of the last row with data
L = lastRow;
theRow = 2;//Start in row 2
for (i=0;i<L;i++) {//Loop as many times as there is number of rows with data
theColumn = 3;//Column C
theRng = sh.getRange(theRow,theColumn);//Get the range which is one cell
currVal = theRng.getValue();//Get the value in one cell
//Logger.log('currVal: ' + currVal);
if (!currVal) {//If there is a blank cell then
break;//quit the loop
}
plusVal= currVal +1;
theRng.setValue(plusVal);
theColumn = 2;//Column B
theRng = sh.getRange(theRow,theColumn);
currVal = theRng.getValue();
minusVal = currVal - 1;
theRng.setValue(minusVal);
if (!currVal) {//If there is a blank cell then
break;//quit the loop
}
theRow = theRow + 1;//Increment to the next row
}
}catch(e) {
Logger.log('message: ' + e.message);
Logger.log('stack: ' + e.stack);
}
}