我正在尝试使用ajax post方法而非jQuery 制作提交表单的订阅者表单。我写了一个代码,但它没有正常工作,我认为我在发送POST数据时做错了。这是我迄今为止尝试过的代码。
<div id="form" style="max-width:477px">
<div class="imgContainer" id="myImageContainer">
<span onclick="document.getElementById('myLogin').style.display='none'" class="close" title="Close">×</span>
</div>
<div class="loginInfo" id="myLoginInfo">
<label for="Full Name">
<b>Full Name</b>
</label>
<spam class="error" style="color:red">
<i id="nameErr"></i>
</spam>
<input type="text" placeholder="Enter full name" name="name" id="name">
<label for="Email"><b>Email</b></label>
<spam class="error" style="color:red">
<i id="emailErr"> </i>
</spam>
<input type="text" placeholder="Enter your Email" name="email" id="email">
<button onclick="verify()">Subscribe</button>
</div>
</div>
</div>
<script>
function verify(){
var xmlhttp = new XMLHttpRequest();
xmlhttp.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
myObj = JSON.parse(this.responseText);
document.getElementById("email").innerHTML = myObj.email;
document.getElementById("emailErr").innerHTML = myObj.emailErr;
document.getElementById("name").innerHTML = myObj.name;
document.getElementById("nameErr").innerHTML = myObj.nameErr;
}
};
xmlhttp.open("GET", "subs.php", true);
var data="email=" + document.getElementById("email").value + "&name="+document.getElementById("name").value;
xmlhttp.send(data);
}
</script>
并且PHP页面看起来像这样(使用HTML时它工作正常&lt; Form method =&#34; post&#34;&gt;
if ($_SERVER["REQUEST_METHOD"] == "POST") {
$email = $name = $emailErr = $nameErr="";
function test($data) {
$data = trim($data);
$data = stripslashes($data);
$data = htmlspecialchars($data);
return $data;
}
if (empty($_POST["email"])) {
$emailErr=" *This Field is Required";
}else{
$email=test($_POST["email"]);
if (!filter_var($email, FILTER_VALIDATE_EMAIL)){$emailErr = " *Invalid email format";}
if (strlen($email)>60){$emailErr=" *Email cannot be larger than 60 character";}
}
if (empty($_POST["name"])) {
$nameErr=" *This Field is Required";
}else{
$name = test($_POST["name"]);
$name = preg_replace('/\s\s+/', ' ', $name);
if (!preg_match("/^[a-zA-Z ]*$/",$name)) {
$nameErr = " *Only letters and white space allowed";
}
if (strlen($name)>60)
{$nameErr=" *Name cannot be larger than 60 character";}
}
$json['email'] = $email;
$json['emailErr'] = $emailErr;
$json['name'] = $name;
$json['nameErr'] = $nameErr;
$myJSON = json_encode($json);
echo $myJSON;
}
当我点击订阅按钮时,它会给我空值而不是显示错误消息。
答案 0 :(得分:0)
xmlhttp.open("GET", "subs.php", true);
应该是
xmlhttp.open("POST", "subs.php", true);
如果PHP代码需要POST请求。
答案 1 :(得分:0)
建议你发送带有Axios的ajax比Jquery和纯javascript更简单明了