为什么我找不到我的着色器属性?

时间:2018-05-26 08:05:27

标签: c++ opengl attributes shader

我正在创建一个简单的opengl程序。编译并链接我的着色器程序后,我尝试使用glGetAttribLocation()检索输入属性,但它返回-1。

我编译并链接我的程序如下:

GLuint vsID = glCreateShader(GL_VERTEX_SHADER);
GLuint fsID = glCreateShader(GL_FRAGMENT_SHADER);

char vsSource[] = "#version 330 core\n\
in vec4 position;\
void main(void)\
{\
  gl_Position = position;\
}";

char fsSource[] = "#version 330\n\
out vec4 color;\
void main(void)\
{\ 
  color = vec4(1.0, 0.0, 0.0, 1.0);\
}";

const char *p_vsSrc = &vsSource[0];
const char *p_fsSrc = &fsSource[0];

glShaderSource(vsID, 1, &p_vsSrc, nullptr);
glShaderSource(fsID, 1, &p_fsSrc, nullptr);

glCompileShader(vsID);
glCompileShader(fsID);

//Check shader for errors
GLint vsCompiled = GL_FALSE;
GLint fsCompiled = GL_FALSE;
glGetShaderiv(vsID, GL_COMPILE_STATUS, &vsCompiled);
glGetShaderiv(fsID, GL_COMPILE_STATUS, &fsCompiled);
if (vsCompiled != GL_TRUE)
{
  //Error...
}
if (fsCompiled != GL_TRUE)
{
  //Error...
}

GLuint shaderProgram = glCreateProgram();
glAttachShader(shaderProgram, vsID);
glAttachShader(shaderProgram, fsID);
glLinkProgram(shaderProgram);

这个编译和链接很好。此外,我在代码中对glGetError()的任何调用都会返回0。

但我无法检索position的位置:

GLuint vPosition = glGetAttribLocation(shaderProgram, "position");
//position == -1

为什么会这样?

1 个答案:

答案 0 :(得分:2)

您必须验证着色器程序是否已正确链接,因为glGetAttribLocation会查询链接程序的属性变量的位置。属性(或程序输入)是程序资源,其位置在链接程序时确定:

glLinkProgram( shaderProgram );
GLint status = GL_TRUE;
glGetProgramiv( shaderProgram, GL_LINK_STATUS, &status );
if ( status == GL_FALSE )
{
    GLint logLen;
    glGetProgramiv( shaderProgram, GL_INFO_LOG_LENGTH, &logLen );
    std::vector< char >log( logLen );
    GLsizei written;
    glGetProgramInfoLog( shaderProgram, logLen, &written, log.data() );
    std::cout  << "link error:" << std::endl << log.data() << std::endl;

    .....
}