支持

Question

我有一个包含组件列表的屏幕。当我向下滚动屏幕时，从按钮转到下一个屏幕（比如第20个组件）并返回上一个屏幕，返回btn，前一个屏幕（带有组件列表）显示第一个组件。如何在支持时显示带有第20个组件的屏幕？

观看视频here

Container mainContainer = new Container(new BoxLayout(BoxLayout.Y_AXIS));
mainContainer.setScrollableY(true);
for (Map<String, Object> entrySet : protectedPlantsList) {
    String title = entrySet.get("title").toString();
    String sname = entrySet.get("sname").toString();
    String nname = entrySet.get("nname").toString();

    Label plantSpeciesLabel = new Label(title);
    TextArea family = new TextArea(sname);
    TextArea nepaliName = new TextArea(nname);
    _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ 
    _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ 

    Button infoIcon1 = new Button("", "TextField");
    infoIcon1.addActionListener(e -> {
        new ThreatCategory(res, threatData1.getName(), infoIcon1.getName(), threatList).show();
    });
    mainContainer.add(BorderLayout.centerEastWest(plantSpeciesLabel, ...., .....));
}

更新1 ：

ProtectedPlantAndSpecies类：

Container mainContainer = new Container(new BoxLayout(BoxLayout.Y_AXIS));
mainContainer.setScrollableY(true);
for (Map<String, Object> entrySet : protectedPlantsList) {
    String title = entrySet.get("title").toString();
    String sname = entrySet.get("sname").toString();
    String nname = entrySet.get("nname").toString();

    Label plantSpeciesLabel = new Label(title);
    TextArea family = new TextArea(sname);
    TextArea nepaliName = new TextArea(nname);
    _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ 
    _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ 

    Button infoIcon1 = new Button("", "TextField");
    infoIcon1.addActionListener(e -> {
        Form myDestinationForm = new ThreatCategory(res, cat, cat_description, threatList);
        myDestinationForm.addShowListener(f -> infoIcon1.requestFocus());
        myDestinationForm.show();
    });
    mainContainer.add(BorderLayout.centerEastWest(plantSpeciesLabel, ...., .....));
}

ThreatCategory类：

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Command backCommand = new Command("Back", backFontImage) {
    @Override
    public void actionPerformed(ActionEvent evt) {
        new ProtectedPlantAndSpecies(res, true).show();
    }
};

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Answer 1

做这样的事情：

Form hi = new Form("Last", BoxLayout.y());
Button t = new Button("Next");
hi.add(t);
t.addActionListener(e -> {
    Form f = new Form("Showing Last", BoxLayout.y());
    for(int iter = 0 ; iter < 20 ; iter++) {
        f.add(new Button("Button " + iter));
    }
    Button last = new Button("Last");
    f.add(last);
    f.addShowListener(ee -> last.requestFocus());
    f.show();
});