Question

我正在开发一个Laravel项目，并遇到了问题，我从数据库中得到2件事（费用和付款），它返回一个集合对象。我需要按密钥对它们进行分组，这里是数组：

    [items:protected] => Array
    (
        [0] => stdClass Object
            (
                [date_payment] => 2018-01-01
                [total_payment] => 19761.62
            )

    )

)

Illuminate\Support\Collection Object
(
[items:protected] => Array
    (
        [0] => stdClass Object
            (
                [date_payment] => 2018-01-29
                [total_charges] => 5184.4399862289
            )

        [1] => stdClass Object
            (
                [date_payment] => 2017-09-04
                [total_charges] => 0
            )

    )

 )

我需要它像那样：

Illuminate\Support\Collection Object
(
[items:protected] => Array
    (
        [0] => stdClass Object
            (
                [date_payment] => 2018-01-29
                [total_charges] => 5184.4399862289
                [total_payment] => 19761.62
            )

        [1] => stdClass Object
            (
                [date_payment] => 2017-09-04
                [total_charges] => 0
            )

    )

   )

我已尝试过所有内容，我查看了Google，查看了Laravel文档：我没有看到任何操作，我尝试使用union / merge方法，但是没有做我想要的操作< / p>

感谢您的帮助！

Answer 1

假设您有一个名为$payments的集合：

$payment = new StdClass;
$payment->date_payment = '2018-01-01';
$payment->total_payment = 19761.62;

$payments = collect([
    $payment
]);

另一个名为$expenses的集合：

$expense1 = new StdClass();
$expense1->date_payment = '2018-01-29';
$expense1->total_charges = 5184.4399862289;

$expense2 = new StdClass();
$expense2->date_payment = '2017-09-04';
$expense2->total_charges = 0;

$expenses = collect([
    $expense1, $expense2
]);

要检索两个集合中具有相同键的元素，您可以使用intersectByKeys执行此操作：

$payments->intersectByKeys($expenses);

这将检索具有费用集合的公共密钥的所有付款。

现在，要更新集合的值，您可以使用transform函数：

$payments->transform(function ($payment, $index) use ($expenses) {
    $expense = $expenses->get($index);
    $payment->date_payment = $expense->date_payment;
    $payment->total_charges = $expense->total_charges;

    return $payment;
});

现在，如果将两者结合在一起：

$payments->intersectByKeys($expenses)->transform(function ($payment, $index) use ($expenses) {
    $expense = $expenses->get($index);
    $payment->date_payment = $expense->date_payment;
    $payment->total_charges = $expense->total_charges;

    return $payment;
});

输出

Collection {#277 ▼
  #items: array:1 [▼
    0 => {#272 ▼
      +"date_payment": "2018-01-29"
      +"total_payment": 19761.62
      +"total_charges": 5184.4399862289
    }
  ]
}

了解更多信息：

Laravel group 2按键收集

1 个答案:

输出