我从一个看起来像这样的表(非常简化)中获取JSON数据:
我得到的JSON格式如下:
const myObjOriginal = {
"rows": [{
"name": "row 1",
"cells": [{
"name": "level 1",
"id": 1
}, {
"name": "first level 2",
"id": 2
}, {
"name": "endpoint 1",
"id": 4
}]
}, {
"name": "row 2",
"cells": [{
"name": "level 1",
"id": 1
}, {
"name": "first level 2",
"id": 2
}, {
"name": "endpoint 2",
"id": 5
}]
}, {
"name": "row 3",
"cells": [{
"name": "level 1",
"id": 1
}, {
"name": "second level 2",
"id": 3
}, {
"name": "endpoint 3",
"id": 6
}]
}]
};
我需要做的就是把它变成树而不是表,输出看起来像这样:
const goalObject = [{
"name": "level 1",
"id": 2,
"children": [{
"name": "first level 2",
"id": 2,
"children": [{
"name": "endpoint 1",
"id": 4
}, {
"name": "endpoint 2",
"id": 5
}]
}, {
"name": "second level 2",
"id": 3,
"children": [{
"name": "endpoint 3",
"id": 6
}]
}]
}];
我尝试了各种各样的事情,包括map,reduce,filter,for循环和forEach,但都无济于事。
我意识到我需要以某种方式制作一个递归函数,但我还没有这样做。
这是我尝试过的一件事的例子,但我知道这是完全错误的......
function getChildrenOfCurrentItem(rowIndex = 0, cellIndex = 0) {
let current = {};
let myObj = {};
for(let i = 0; i < myCopy.rows.length; i++){
next = myCopy.rows[i].cells[cellIndex];
const cells = myCopy.rows[i].cells;
const isSame = compareObjects(current, next);
if(!isSame){
current = next;
myObj.item = current;
//cellIndex++;
for(let j = 0; j < cells.length; j++){
let cell = cells[j];
console.log('cell', cell);
}
}
console.log('myObj', myObj);
//cellIndex++;
if(cellIndex < max) {
getChildrenOfCurrentItem(rowIndex, cellIndex);
}
rowIndex++;
}
return myObj;
}
答案 0 :(得分:1)
您可以通过查找具有相同id
的组来使用迭代方法。
var data = { rows: [{ name: "row 1", cells: [{ name: "level 1", id: 1 }, { name: "first level 2", id: 2 }, { name: "endpoint 1", id: 4 }] }, { name: "row 2", cells: [{ name: "level 1", id: 1 }, { name: "first level 2", id: 2 }, { name: "endpoint 2", id: 5 }] }, { name: "row 3", cells: [{ name: "level 1", id: 1 }, { name: "second level 2", id: 3 }, { name: "endpoint 3", id: 6 }] }] },
result = [];
data.rows.forEach(({ cells }) => {
cells.reduce((level, { name, id }) => {
var temp = (level.children = level.children || []).find(o => o.id === id);
if (!temp) {
temp = { name, id };
level.children.push(temp);
}
return temp;
}, { children: result });
});
console.log(result);
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