Question

我对正则表达式不是很好

我想要一个匹配这些的正则表达式：

http://localhost:3000/categories/football
http://localhost:3000/categories/football/2222/45444
http://localhost:3000/categories/tennis/45454
http://localhost:3000/categories/football/12
http://localhost:3000/categories/cricket/

基本上，对于以上所有可能的网址路径，我希望返回categories/之后和第二个/之前的字词

即

足球，足球，网球，足球，板球

我到目前为止： (categories)/\w+

但很明显，这仍然包括类别

Answer 1

您可以将捕获组从(categories)更改为(\w+)并使用正向前瞻(?=来断言后面的内容是可选的(?=\/?)正斜杠。

您要查找的值位于捕获的第1组中。

categories\/(\w+)(?=\/?)

const strings = [
  "http://localhost:3000/categories/football",
  "http://localhost:3000/categories/football/2222/45444",
  "http://localhost:3000/categories/tennis/45454",
  "http://localhost:3000/categories/football/12",
  "http://localhost:3000/categories/cricket/"
];
let pattern = /categories\/(\w+)(?=\/?)/;

strings.forEach((s) => {
  console.log(s.match(pattern)[1]);
});

Answer 2

为什么不拆分 - 如果类别是路径名中的第二个

var loc = "/categories/football/2222/45444"; // var loc = location.pathname
console.log(loc.split("/")[2])

Answer 3

你走了。

＆＃13;

var url1 = "http://localhost:3000/categories/football"
var url2 = "http://localhost:3000/categories/football/2222/45444"
var url3 = "http://localhost:3000/categories/tennis/45454"
var url4 = "http://localhost:3000/categories/football/12"
var url5 = "http://localhost:3000/categories/cricket/"

var regex = /categories\/(\w+)(?=\/?)/;
console.log(regex.exec(url1)[1]);
console.log(regex.exec(url2)[1]);
console.log(regex.exec(url3)[1]);
console.log(regex.exec(url4)[1]);
console.log(regex.exec(url5)[1]);

＆＃13;

Answer 4

您可以使用RegEx (?<=categories\/)[^\/\n]+

(?<=categories\/)确保您的匹配前面有categories/
[^\/\n]+只匹配/或newline 1次或以上的任何内容

Demo at Regex101.

var re =  /(?<=categories\/)[^\/\n]+/
console.log(
"http://localhost:3000/categories/football/2222/45444".match(re)[0]
)

Answer 5

您可以从捕获组中排除类别

let regex = /(?:categories)+(\/\w+)/;
urls.forEach((str) => {
  console.log(str.match(regex)[1].replace('/',''));
});

如何使用正则表达式在url中获取路径

5 个答案: