Question

我试图在Selenium和Python中找到一个损坏的链接，但在代码中出错：

import requests
from selenium import webdriver

chrome_driver_path = "D:\\drivers\\chromedriver.exe"

driver=webdriver.Chrome(chrome_driver_path)

driver.get('https://google.co.in/')
links = driver.find_elements_by_css_selector("a")
images = driver.find_elements_by_css_selector("img")
for link in links:
    r = requests.head(link.get_attribute('href')
    print(r.status_code == 200)

无法在页面上找到损坏的链接是否有其他解决方案？

获得：

引发MaxRetryError（_pool，url，error或ResponseError（cause）） urllib3.exceptions.MaxRetryError： HTTPSConnectionPool（host ='myaccount.google.com'，port = 443）：最多使用url超出重试次数：/？utm_source = OGB＆amp; utm_medium = app（由 SSLError（SSLEOFError（8，'EOF违反协议发生）（_ssl.c：777）'），））

在处理上述异常期间，发生了另一个异常：

self._sslobj.do_handshake（）ssl.SSLEOFError：EOF违规发生协议（_ssl.c：777）

在处理上述异常期间，发生了另一个异常：

追踪（最近一次呼叫最后一次）：

Answer 1

因为您在下面的行中缺少右括号或是错字吗？

r = requests.head(link.get_attribute('href'))

Answer 2

要查找页面上链接的状态，您可以使用以下解决方案：

代码块：

import requests
from selenium import webdriver

options = webdriver.ChromeOptions() 
options.add_argument("start-maximized")
options.add_argument('disable-infobars')
driver=webdriver.Chrome(chrome_options=options, executable_path=r'C:\Utility\BrowserDrivers\chromedriver.exe')
driver.get('https://google.co.in/')
links = driver.find_elements_by_css_selector("a")
for link in links:
    r = requests.head(link.get_attribute('href'))
    print(link.get_attribute('href'), r.status_code)

控制台输出：

https://mail.google.com/mail/?tab=wm 302
https://www.google.co.in/imghp?hl=en&tab=wi 200
https://www.google.co.in/intl/en/options/ 301
https://myaccount.google.com/?utm_source=OGB&utm_medium=app 302
https://www.google.co.in/webhp?tab=ww 200
https://maps.google.co.in/maps?hl=en&tab=wl 302
https://www.youtube.com/?gl=IN 200
https://play.google.com/?hl=en&tab=w8 302
https://news.google.co.in/nwshp?hl=en&tab=wn 301
https://mail.google.com/mail/?tab=wm 302
https://www.google.com/contacts/?hl=en&tab=wC 302
https://drive.google.com/?tab=wo 302
https://www.google.com/calendar?tab=wc 302
https://plus.google.com/?gpsrc=ogpy0&tab=wX 302
https://translate.google.co.in/?hl=en&tab=wT 200
https://photos.google.com/?tab=wq&pageId=none 302
https://www.google.co.in/intl/en/options/ 301
https://docs.google.com/document/?usp=docs_alc 302
https://books.google.co.in/bkshp?hl=en&tab=wp 200
https://www.blogger.com/?tab=wj 405
https://hangouts.google.com/ 302
https://keep.google.com/ 302
https://earth.google.com/web/ 200
https://www.google.co.in/intl/en/options/ 301
https://accounts.google.com/ServiceLogin?hl=en&passive=true&continue=https://www.google.co.in/ 200
https://www.google.co.in/webhp?hl=en&sa=X&ved=0ahUKEwj0qNPqnqHbAhXYdn0KHXpeAo0QPAgD 200

Answer 3

from selenium import webdriver
chrome_driver_path = "D:\\drivers\\chromedriver.exe"
driver=webdriver.Chrome(chrome_driver_path)
import requests
for link in links:
    r = requests.head(link)
    if r.status_code!=404:
         driver.get(link)
    else:
          print(str(link) + " isn't available.")

如何在Selenium + Python中找到损坏的链接

3 个答案: