我的查询
site-packages/sqlalchemy/dialects/oracle/base.px
我想再次比较查询结果列
./base.py:360:RESERVED_WORDS
SELECT
stoMast.sStockistCode,
stoMast.sStateName,
stoMast.sDivision,
stateMap.sRMCode
FROM
tblRSM_State_Mapping stateMap
INNER JOIN
tblStockistMaster stoMast ON
stateMap.sStateName = stoMast.sStateName
WHERE
stateMap.sRMCode = 'MCNE04001'
and
stoMast.sDivision = 'CIDIS'
except
select
sStockistCode,
sStateName,
sDivision,
sRMCode
From
tblEntry
sStockistCode
sStateName
具有相同的字段
sDivision
tblStockistMaster
sStockistCode
并检索STOCKIST NAME。不知道如何将上述查询结果与表格进行比较。
答案 0 :(得分:1)
也许您可以使用以下与CTE表达式
一起使用的SQL代码;with cte as (
SELECT
stoMast.sStockistCode,
stoMast.sStateName,
stoMast.sDivision,
stateMap.sRMCode
FROM
tblRSM_State_Mapping stateMap
INNER JOIN
tblStockistMaster stoMast ON
stateMap.sStateName = stoMast.sStateName
WHERE
stateMap.sRMCode = 'MCNE04001'
and
stoMast.sDivision = 'CIDIS'
except
select
sStockistCode,
sStateName,
sDivision,
sRMCode
From
tblEntry
)
select
cte.*,
sm.sStockistName
from cte
left join tblStockistMaster as sm
on sm.sStockistCode = cte.sStockistCode and
sm.sStateName = cte.sStateName and
sm.sDivision = cte.sDivision
答案 1 :(得分:0)
-- I retrieve the stockist Name
SELECT
stoMast.sStockistName,
FROM
tblRSM_State_Mapping stateMap
INNER JOIN
tblStockistMaster stoMast
ON stateMap.sStateName = stoMast.sStateName
-- I'm joining table entry If I can match
LEFT JOIN
tblEntry tbl
on tbl.sStockistCode = stoMast.sStockistName
AND tbl.sStateName = stoMast.sStateName
AND tbl.sDivision = stoMast.sDivision
AND tbl.sRMCode = stateMap.sRMCode
WHERE
stateMap.sRMCode = 'MCNE04001'
and stoMast.sDivision = 'CIDIS'
-- And The the exept thing, I don't want that got a match with the tableentry
AND COALESCE(tbl.sStockistCode, tbl.sStateName, tbl.sDivision, tbl.sRMCode) is null
我希望这是你想要的。另一方面,请帮助我们了解您的来源(表格和数据的概念)以及您想要的结果。将更容易创建查询。