Xarray可以通过.construct()
对象执行加权滚动均值,如SO here和docs的回答中所述。
文档中的加权滚动平均值示例看起来并不正确,因为它似乎给出了与普通滚动平均值相同的答案。
import xarray as xr
import numpy as np
arr = xr.DataArray(np.arange(0, 7.5, 0.5).reshape(3, 5),
... dims=('x', 'y'))
arr.rolling(y=3, center=True).mean()
#<xarray.DataArray (x: 3, y: 5)>
#array([[nan, 0.5, 1. , 1.5, nan],
# [nan, 3. , 3.5, 4. , nan],
# [nan, 5.5, 6. , 6.5, nan]])
#Dimensions without coordinates: x, y
weight = xr.DataArray([0.25, 0.5, 0.25], dims=['window'])
arr.rolling(y=3, center=True).construct('window').dot(weight)
#<xarray.DataArray (x: 3, y: 5)>
#array([[nan, 0.5, 1. , 1.5, nan],
# [nan, 3. , 3.5, 4. , nan],
# [nan, 5.5, 6. , 6.5, nan]])
#Dimensions without coordinates: x, y
这是一个更简单的例子,我想直接获得语法:
da = xr.DataArray(np.arange(1,6), dims='x')
da.rolling(x=3, center=True).mean()
#<xarray.DataArray (x: 5)>
#array([nan, 2., 3., 4., nan])
#Dimensions without coordinates: x
weight = xr.DataArray([0.5, 1, 0.5], dims=['window'])
da.rolling(x=3, center=True).construct('window').dot(weight)
#<xarray.DataArray (x: 5)>
#array([nan, 4., 6., 8., nan])
#Dimensions without coordinates: x
它返回4,6,8。我以为它会这样做:
(1 x 0.5) + (2 x 1) + (3 x 0.5) / 3 = 4/3
(2 x 0.5) + (3 x 1) + (4 x 0.5) / 3 = 2
(3 x 0.5) + (4 x 1) + (5 x 0.5) / 3 = 8/3
1.33, 2. 2.66
答案 0 :(得分:1)
在第一个示例中,您使用arr
的均匀间隔数据。
因此,加权平均值([0.25,5,50])将与简单mean
相同。
如果考虑非线性数据,结果会有所不同
In [50]: arr = xr.DataArray((np.arange(0, 7.5, 0.5)**2).reshape(3, 5),
...: dims=('x', 'y'))
...:
In [51]: arr.rolling(y=3, center=True).mean()
Out[51]:
<xarray.DataArray (x: 3, y: 5)>
array([[ nan, 0.416667, 1.166667, 2.416667, nan],
[ nan, 9.166667, 12.416667, 16.166667, nan],
[ nan, 30.416667, 36.166667, 42.416667, nan]])
Dimensions without coordinates: x, y
In [52]: weight = xr.DataArray([0.25, 0.5, 0.25], dims=['window'])
...: arr.rolling(y=3, center=True).construct('window').dot(weight)
...:
Out[52]:
<xarray.DataArray (x: 3, y: 5)>
array([[ nan, 0.375, 1.125, 2.375, nan],
[ nan, 9.125, 12.375, 16.125, nan],
[ nan, 30.375, 36.125, 42.375, nan]])
Dimensions without coordinates: x, y
对于第二个示例,使用[0.5,1,0.5]作为权重,总计为2。
因此,第一个非纳米项目将是
(1 x 0.5) + (2 x 1) + (3 x 0.5) = 4
如果你想要加权平均值而不是加权和,请改用[0.25,0.5,0.25]。