Question

我已经为我的python程序构建了一个winform接口，我的python程序是一个实时语音助手，我需要的是接口应该在python提供输出时立即响应。我需要立即向界面显示标准输出。以下程序就是我所做的。

在此代码中，界面没有正确响应。 python程序在后台持续执行而不响应语音。我需要一个程序来执行我的python程序并将标准输出显示到winform接口。

namespace @interface
{
    public partial class Form1 : Form
    {
        public static string text;
        public Form1()
        {
            InitializeComponent();
        }

        private void pictureBox1_Click(object sender, EventArgs e)
        {

        }

        private async void start_button_Click(object sender, EventArgs e)
        {
            string line;
            int counter=0;
            msg.Text = "Hey, Tell me something!";

            Task task = new Task(Execute);
            task.Start();

        }


           public void Execute()
            {
                // full path of python interpreter 
                string python = @"C:/Users/Jayasooryan/AppData/Local/Programs/Python/Python36-32/python.exe";

                // python app to call 
                string myPythonApp = @"C:/Users/Jayasooryan/AppData/Local/Programs/Python/Python36-32/Avira.py";

                // Create new process start info 
                ProcessStartInfo myProcessStartInfo = new ProcessStartInfo(python);

                // make sure we can read the output from stdout 
                myProcessStartInfo.UseShellExecute = false;
                myProcessStartInfo.RedirectStandardOutput = true;
                myProcessStartInfo.CreateNoWindow = true;

                // start python app with 3 arguments  
                // 1st arguments is pointer to itself,  
                // 2nd and 3rd are actual arguments we want to send 
                myProcessStartInfo.Arguments = myPythonApp;

                Process myProcess = new Process();
                // assign start information to the process 
                myProcess.StartInfo = myProcessStartInfo;

                // start the process 
                myProcess.Start();

                // Read the standard output of the app we called.  
                // in order to avoid deadlock we will read output first 
                // and then wait for process terminate: 
                StreamReader myStreamReader = myProcess.StandardOutput;
                string myString = myStreamReader.ReadLine();
                text = myString;


            //Console.WriteLine(myString);

            /*if you need to read multiple lines, you might use: 
                string myString = myStreamReader.ReadToEnd() */

            // wait exit signal from the app we called and then close it. 
            myProcess.WaitForExit();
            myProcess.Close();

            // write the output we got from python app 

            //Console.ReadLine();
        }

        private void textBox1_TextChanged(object sender, EventArgs e)
        {

        }
    }
}

Answer 1

首先：你不应该尝试从python进程中读取一行，而是在进程写入新数据时使用OutputDataReceived事件。

第二：由于输出是缓冲的，你可能想在python进程中写入后刷新它。

所以这是一个简单的python脚本，一直写入标准输出（注意如何调用stdout.flush）：

import random
import time
import sys

while True:
   rand = random.randint(1, 10)
   time.sleep(1)
   print rand
   sys.stdout.flush()
   if rand in (9, 10):
       break

这是一个简单的表单，它读取该脚本的输出：

var f = new Form();
var t = new TextBox();
t.Dock = DockStyle.Fill;
t.Multiline = true;
f.Controls.Add(t);
f.Load += (s, e) => {
    Process process = new Process();
    process.StartInfo.FileName = "python";
    process.StartInfo.Arguments = @"d:\script.py";
    process.StartInfo.UseShellExecute = false;
    process.StartInfo.RedirectStandardOutput = true;
    process.OutputDataReceived += (s2, e2) => {
        t.Text += e2.Data + Environment.NewLine;
    };
    process.Start();
    process.BeginOutputReadLine();
};
f.ShowDialog();

python脚本

1 个答案: