Question

所以我是Python（3）的新手，需要创建一个循环，它将遍历近200个CSV文件并将它们转换为以管道分隔的.txt文件（具有相同的名称）。

我有一个代码可以为1个文件执行此操作并且运行正常：

import csv

with open('C:/Path/InputFile.csv', 'r') as fin, \
open('C:/Path/OutputFile.txt', 'w') as fout:
reader = csv.DictReader(fin)
writer = csv.DictWriter(fout, reader.fieldnames, delimiter='|')
writer.writeheader()
writer.writerows(reader)

提前致谢。

Answer 1

您可以将代码修改为：

                    artist track_title                     lyric     character
1  Claude-Michel Schönberg    Prologue             ["Work Song"] ["Work Song"]
2  Claude-Michel Schönberg    Prologue               [PRISONERS]   [PRISONERS]
3  Claude-Michel Schönberg    Prologue       Aaah, aah, aaaahhhh   [PRISONERS]
4  Claude-Michel Schönberg    Prologue Don't look 'em in the eye         false
5  Claude-Michel Schönberg    Prologue      Look down, look down         false
6  Claude-Michel Schönberg    Prologue You're here until you die         false
7  Claude-Michel Schönberg    Prologue             [PRISONER #1] [PRISONER #1]

您希望分别从中读取和写入的文件的for in_name, out_name in zip(list_of_in_names, list_of_out_names): with open(in_name, 'r') as fin, open(out_name, 'w') as fout: ...和list_of_in_names个名称。

编辑：要解决评论中的问题，您可以使用list_of_out_names库：

pathlib

如何使用Python3将目录中的多个CSV文件转换为管道分隔的文本文件

1 个答案: