Question

我试图通过在Team（Parent）中添加玩家名称并努力尝试获取玩家名称列表来实现嵌套变异......

Inside GraphiQL工具（localhost：4000 / graphiql），这是我添加的Add Mutation变量......

mutation AddPlayerToTeam($name: String!, $teamId: ID!){
  addPlayerToTeam(player: $name, teamId: $teamId){
    id
    players{
      name
    }
  }
}

查询变量，添加teamID和名称......

{
  "teamId": "5aff545371fc930a4c43b2b9",
  "name": "John Doe"
}

结果显示......

{
  "data": {
    "addPlayerToTeam": {
      "id": "5b072774e385740c38483111",
      "players": []
    }
  }
}

但我期待球员名字能够像这样出现......

{
  "data": {
    "addPlayerToTeam": {
      "id": "5b072774e385740c38483111",
      "players": [
         { 
           "name": "John Doe"
         }
       ]
     }
  }
}

突变代码......

AddPlayerToTeam: {
    type: TeamType,
    args: {
            name: { type: new GraphQLNonNull(GraphQLString) },
            teamId: { type: new GraphQLNonNull(GraphQLID) }
        },
        resolve(parent, { name, teamId }) {
            let addPlayer = new Player({ name, teamId });
            return addPlayer.save();
        }
    },

我很难找到为什么我会收到"players": []而不是"players": [ {"name": "John Doe" } ]的原因。我需要在.then(...)之后加入.save()才能获得结果吗？任何例子？感谢您的帮助。

BTW，我使用的是mongoDB / mongoose方法。将它们保存在本地mongoDB中。

Answer 1

为此找到解决方案...感谢graphql.slack中的#andrewingram提供帮助。只需包含.then(...)即可返回结果。

AddPlayerToTeam: {
    type: TeamType,
    args: {
        name: { type: new GraphQLNonNull(GraphQLString) },
        teamId: { type: new GraphQLNonNull(GraphQLID) }
    },
    async resolve(parent, { name, teamId }) {
        let addPlayer = new Player({ name, teamId });
        await addPlayer.save();
        return Team.findById(teamId);
    }
},

或承诺版

resolve(parent, { name, teamId }) {
        let addPlayer = new Player({ name, teamId });
        return addPlayer.save().then(() => Team.findById(teamId));
    }

希望有所帮助。

GraphQL嵌套变异的问题

1 个答案: