我试图从网址下载所有文件。但是,通过chrome开发人员工具分析代码,我可以看到我需要的文件在路径中作为示例: /var/www/html/folders_and_files_that_i_need
。
有人有任何想法可以帮助我吗?提前谢谢。
我的代码实际上只能下载文件设置绝对路径。
public static void downloadFile(String fileURL, String saveDir) throws IOException {
URL url = new URL(fileURL);
HttpURLConnection httpConn = (HttpURLConnection) url.openConnection();
int responseCode = httpConn.getResponseCode();
// always check HTTP response code first
if (responseCode == HttpURLConnection.HTTP_OK) {
String fileName = "";
String disposition = httpConn.getHeaderField("Content-Disposition");
String contentType = httpConn.getContentType();
int contentLength = httpConn.getContentLength();
if (disposition != null) {
// extracts file name from header field
int index = disposition.indexOf("filename=");
if (index > 0) {
fileName = disposition.substring(index + 10, disposition.length() - 1);
}
} else {
// extracts file name from URL
fileName = fileURL.substring(fileURL.lastIndexOf("/") + 1, fileURL.length());
}
System.out.println("Content-Type = " + contentType);
System.out.println("Content-Disposition = " + disposition);
System.out.println("Content-Length = " + contentLength);
System.out.println("fileName = " + fileName);
// opens input stream from the HTTP connection
InputStream inputStream = httpConn.getInputStream();
String saveFilePath = saveDir + File.separator + fileName;
// opens an output stream to save into file
FileOutputStream outputStream = new FileOutputStream(saveFilePath);
int bytesRead = -1;
byte[] buffer = new byte[BUFFER_SIZE];
while ((bytesRead = inputStream.read(buffer)) != -1) {
outputStream.write(buffer, 0, bytesRead);
System.out.println("buffering");
}
outputStream.close();
inputStream.close();
System.out.println("Arquivo " + fileName + " baixado");
} else {
System.out.println("No file to download. Server replied HTTP code: " + responseCode);
}
httpConn.disconnect();
}
答案 0 :(得分:2)
在REST API中,您必须拥有单个文件的资源 Java download all files and folders in a directory
可能会帮助你。
答案 1 :(得分:1)
您可以使用以下逻辑:
以下是对此的解释:
使用递归算法获取该文件夹中的所有完整文件路径。
您可以使用下面的代码来获取使用递归获取文件夹中的所有文件,此代码已被采用from here
// Recursive Java program to print all files
// in a folder(and sub-folders)
import java.io.File;
public class GFG
{
static void RecursivePrint(File[] arr,int index,int level)
{
// terminate condition
if(index == arr.length)
return;
// tabs for internal levels
for (int i = 0; i < level; i++)
System.out.print("\t");
// for files
if(arr[index].isFile())
System.out.println(arr[index].getName());
// for sub-directories
else if(arr[index].isDirectory())
{
System.out.println("[" + arr[index].getName() + "]");
// recursion for sub-directories
RecursivePrint(arr[index].listFiles(), 0, level + 1);
}
// recursion for main directory
RecursivePrint(arr,++index, level);
}
// Driver Method
public static void main(String[] args)
{
// Provide full path for directory(change accordingly)
String maindirpath = "C:\\Users\\Gaurav Miglani\\Desktop\\Test";
// File object
File maindir = new File(maindirpath);
if(maindir.exists() && maindir.isDirectory())
{
// array for files and sub-directories
// of directory pointed by maindir
File arr[] = maindir.listFiles();
System.out.println("**********************************************");
System.out.println("Files from main directory : " + maindir);
System.out.println("**********************************************");
// Calling recursive method
RecursivePrint(arr,0,0);
}
}
}
要制作zip并从servlet下载,您可以浏览此链接 Using a servlet, how do you download multiple files from a database and zip them for client download