Question

我有一个带有ClaimNumber，NoteCreateDate，NoteType

的表

我想找到包含“已发送评论”等声明的声明。在NoteCreateDate

中没有间隙地背靠背

例如。

+-------------+----------------+--------------------+----------+
| ClaimNumber | NoteCreateDate |       Notes        | NoteType |
+-------------+----------------+--------------------+----------+
|       12121 | 12/01/2017     | ReviewSent         | Subject  |
|       12121 | 12/05/2017     | PackagesenttoABC   | Details  |
|       12121 | 12/07/2017     | ReviewSent         | Subject  |
|       10005 | 05/06/2018     | ReviewSent         | Subject  |
|       10005 | 05/07/2018     | ReviewSent         | Subject  |
|       10005 | 05/08/2018     | ReviewSent         | Subject  |
|       10005 | 05/12/2018     | Fieldinvestigation | SIU      |
+-------------+----------------+--------------------+----------+

预期在此示例中，我只想要声明号 10005 ，因为声明中包含“发送的评论”和“已发送的评论”。背靠背，日期没有间隙（连续日期）。例如，我想找到带有短语＆＃39; ReviewSent＆＃39;今天创建并且以下注释也应该相同＆＃39;评论已发送＆＃39;，无论何时创建，可能是第二天甚至10天后...在此先感谢

我当前的MS SQL查询。

    select cm.ClaimNum, a.NoteCreateDate, a.Notes, a.NoteType 
        from CMaster cm
        left join Note a on cm.ClaimNum = a.PARENTREF
        left join NoteType] b on b.ID = a.TYPECODE 
        where Body like '%Review Sent%'

Answer 1

因此，如果您想要找回ReviewSent备注发回的ClaimNumber，那么此查询将获得它们

CREATE TABLE T1
    ([ClaimNumber] int, [NoteCreateDate] datetime, [Notes] varchar(18), [NoteType] varchar(7))
;

INSERT INTO T1
    ([ClaimNumber], [NoteCreateDate], [Notes], [NoteType])
VALUES
    (12121, '2017-12-01 00:00:00', 'ReviewSent', 'Subject'),
    (12121, '2017-12-05 00:00:00', 'PackagesenttoABC', 'Details'),
    (12121, '2017-12-07 00:00:00', 'ReviewSent', 'Subject'),
    (10005, '2018-05-06 00:00:00', 'ReviewSent', 'Subject'),
    (10005, '2018-05-07 00:00:00', 'ReviewSent', 'Subject'),
    (10005, '2018-05-08 00:00:00', 'ReviewSent', 'Subject'),
    (10005, '2018-05-12 00:00:00', 'Fieldinvestigation', 'SIU')
;

SELECT DISTINCT X.ClaimNumber
FROM(
    SELECT
         ClaimNumber
        ,NoteCreateDate
        ,Notes
        ,NoteType
        ,LD=LEAD( Notes )OVER(PARTITION BY ClaimNumber ORDER BY NoteCreateDate ASC)
    FROM dbo.T1
) X WHERE LD= 'ReviewSent' AND X.Notes= 'ReviewSent'

DROP TABLE dbo.T1

结果

ClaimNumber
10005

Answer 2

    Select * into #tmp
    from
   (
       Select   12121  as ClaimNumber,'12/01/2017' as 
      NoteCreateDate,'ReviewSent' as Notes,'Subject' as NoteType
     union
     Select 12121 , '12/05/2017'     , 'PackagesenttoABC'   , 'Details'  
     union
     Select       12121 , '12/07/2017'     , 'ReviewSent'         , 
     'Subject'  
     union
    Select       10005 , '05/06/2018'     , 'ReviewSent'         , 'Subject'  
   union
     Select       10005 , '05/07/2018'     , 'ReviewSent'         , 
       'Subject'  
   union
   Select       10005 , '05/08/2018'     , 'ReviewSent'         , 'Subject'  
     union
  Select       10005 , '05/12/2018'     , 'Fieldinvestigation' , 'SIU'  

  ) t

/*create another temp table to simplify the query*/
 Select * , ROW_NUMBER() OVER (PARTITION BY ClaimNumber ORDER BY 
 ClaimNumber) 
  as ClaimCounter  into #tmp2 from #tmp

  /** finally get the claimnos that have consecutive NoteCreate Date **/
  SELECT distinct t1.ClaimNumber FROM #tmp2 t1
   inner join #tmp2 t2 on (t1.ClaimCounter = t2.ClaimCounter - 1 and 
   t1.ClaimNumber = t2.ClaimNumber)
  where 
  DATEDIFF(DAY,t1.NoteCreateDate,t2.NoteCreateDate) = 1 
  and
  t1.Notes ='ReviewSent' and t2.Notes ='ReviewSent'

用于查找日期中没有间隙的结果的SQL查询

2 个答案: