我在显示 ProgressDialog :
时遇到问题以下代码段在示例中显示了我的代码:
public override void OnActivityCreated(Bundle savedInstanceState)
{
base.OnActivityCreated(savedInstanceState);
progressDialog = new ProgressDialog(Context);
progressDialog.SetCancelable(false);
progressDialog.SetMessage("Saving ...");
}
private void Method()
{
progressDialog.Show();
var testDialog = progressDialog.IsShowing;
SaveImage();
}
private void SaveImage()
{
// does lot
...
// especially this method takes some time
mutableBitmap.Compress(Bitmap.CompressFormat.Png, 100, stream);
}
我创建了一个ProgressDialog,我想在调用 SaveImage 方法之前显示它(并在 SaveImage 完成时取消它)。
我的问题是在 SaveImage 方法完成之前不会显示ProgressDialog。
在调试模式下, progressDialog.IsShowing true ,在调用 SaveImage -Method之前,但不会显示。< / p>
答案 0 :(得分:0)
你必须将你的IO相关代码转移到后台线程,你可以使用asynctask来实现这个
private class AsyncTaskRunner extends AsyncTask<String, String, String> {
private String resp;
ProgressDialog progressDialog;
@Override
protected String doInBackground(String... params) {
saveImage();
}
@Override
protected void onPostExecute(String result) {
// execution of result of Long time consuming operation
progressDialog.dismiss();
}
@Override
protected void onPreExecute() {
progressDialog = ProgressDialog.show(getContext(),
"ProgressDialog",
"Loading");
}
}
答案 1 :(得分:0)
我找到了一个适合我的解决方案:
private async void Method()
{
progressDialog.Show();
var thread = new System.Threading.Thread(new ThreadStart(delegate
{
SaveImage();
}));
thread.Start();
while(thread.ThreadState == ThreadState.Running)
{
await Task.Delay(100);
}
progressDialog.Dismiss();
}
与此同时,我将此代码外包给public static class ThreadHelper
,只需要一个Action(在本例中为 SaveImage())和一个ProgressDialog作为参数。