我需要在使用后明确删除灯具。我知道pytest-django默认会丢弃所有对象,但在这种特殊情况下我需要手动完成。但是,虽然我的测试标记为pytest.mark.django_db
,但我可以创建一个灯具,但无法在yield
行后删除它:
import pytest
from tgapps.models import TelegramApp
@pytest.fixture(scope='module')
def some_fixture():
app = TelegramApp.objects.create(
session_data=b'\xa2\x8f#',
app_owner_phone=79856235474,
app_id=182475,
app_hash='aad9ab4384fea1af0342b77b606d13b0'
)
yield app
print('deleting object...')
app.delete()
class TestTelegramServiceObject(object):
@pytest.mark.django_db
def test1(self, some_fixture):
print('Fixture created:')
print(some_fixture)
这是我的测试输出:
============================= test session starts ==============================
platform darwin -- Python 3.6.4, pytest-3.4.0, py-1.5.2, pluggy-0.6.0
Django settings: inviter.settings.staging (from ini file)
rootdir: /Users/1111/_projects/fasttrack/inviter, inifile: pytest.ini
plugins: mock-1.7.1, dotenv-0.1.0, django-3.1.2
collected 1 item
test_example.py E.Fixture created:
<79856235474 - 182475>
deleting object...
tests/api/test_example.py:25 (TestTelegramServiceObject.test1)
@pytest.fixture(scope='module')
def some_fixture():
app = TelegramApp.objects.create(
session_data=b'\xa2\x8f#',
app_owner_phone=79856235474,
app_id=182475,
app_hash='aad9ab4384fea1af0342b77b606d13b0'
)
yield app
print('deleting object...')
> app.delete()
test_example.py:21:
_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
/Users/1111/.virtualenvs/inviter-WB5rPISo/lib/python3.6/site-packages/django/db/models/base.py:890: in delete
collector.collect([self], keep_parents=keep_parents)
/Users/1111/.virtualenvs/inviter-WB5rPISo/lib/python3.6/site-packages/django/db/models/deletion.py:221: in collect
elif sub_objs:
/Users/1111/.virtualenvs/inviter-WB5rPISo/lib/python3.6/site-packages/django/db/models/query.py:276: in __bool__
self._fetch_all()
/Users/1111/.virtualenvs/inviter-WB5rPISo/lib/python3.6/site-packages/django/db/models/query.py:1179: in _fetch_all
self._result_cache = list(self._iterable_class(self))
/Users/1111/.virtualenvs/inviter-WB5rPISo/lib/python3.6/site-packages/django/db/models/query.py:53: in __iter__
results = compiler.execute_sql(chunked_fetch=self.chunked_fetch, chunk_size=self.chunk_size)
/Users/1111/.virtualenvs/inviter-WB5rPISo/lib/python3.6/site-packages/django/db/models/sql/compiler.py:1062: in execute_sql
cursor = self.connection.cursor()
/Users/1111/.virtualenvs/inviter-WB5rPISo/lib/python3.6/site-packages/django/db/backends/base/base.py:255: in cursor
return self._cursor()
_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
self = <django.db.backends.postgresql.base.DatabaseWrapper object at 0x1048bf080>
name = None
def _cursor(self, name=None):
> self.ensure_connection()
E Failed: Database access not allowed, use the "django_db" mark, or the "db" or "transactional_db" fixtures to enable it.
这是为什么?以及如何在灯具拆卸时启用DB评估?
答案 0 :(得分:0)
您需要在some_fixture中使用db
固定装置:
def some_fixture(db):
...
答案 1 :(得分:0)
安德烈亚斯·普罗夫斯(Andreas Profous)提到的db
固定装置具有功能范围,因此在这里不起作用。
您需要做的是:
@pytest.fixture(scope='module')
def some_fixture(django_db_setup, django_db_blocker):
with django_db_blocker.unblock():
app = TelegramApp.objects.create(
session_data=b'\xa2\x8f#',
app_owner_phone=79856235474,
app_id=182475,
app_hash='aad9ab4384fea1af0342b77b606d13b0'
)
yield app
with django_db_blocker.unblock():
print('deleting object...')
app.delete()
django_db_setup
确保已设置(并准备好)测试数据库以添加其他记录。 django_db_blocker
固定装置使用db
来实现函数范围的修改。之所以对函数进行范围划分是因为,它将表现出TestCase
方法在默认的unittest框架中的行为,该框架在每次测试后都会回滚记录。这是一件好事,它可以确保在一个测试中修改记录不会改变另一个测试中的结果。
因此,在创建不在功能范围内的灯具时要非常小心,因为默认情况下,您的修改不会包装在事务中并回滚。使用django_db_blocker
可以吸引您进入django_db_blocker.unblock()
方法,该方法从修改数据库中删除了该块。在非功能范围内的灯具中,这是必需的。