Question

我有如下所示的代码，最后我已经展示了当用户将传递字符串参数时将如何调用它，他将接收字符串参数，我的问题是有人可以告诉我如何user将对象类型作为参数传递

来调用我的代码

下面是界面

interface applyBuisnessRule<T> {
    public T execute(String jobCode) throws Exception;
}

下面是班级

class CardvaletImpl<T> implements applyBuisnessRule<T> {
    private static final String Success = null;

    public T execute(String jobCode) throws Exception {
        T result = null;
         // put your logic and populate result here. I believe you are not going to return Success every time as it String
        return result;
    }
}

现在这段代码将字符串作为参数传递

CardvaletImpl<String> cardvaletImpl = new CardvaletImpl<>();
String result = cardvaletImpl.execute("JOBCODE");

请告知我如何将对象作为参数传递并获取对象作为回报，就像我在上面对字符串

的情况所做的那样

另请注意我如何将下面的类也作为泛型，因为这是调用我上面的类的上下文类

public class BuisnessRuleContext {



    private  Object Object = null;
    private applyBuisnessRule buisnessRuleName;

    public void setAbr(applyBuisnessRule abr) {
        this.buisnessRuleName = abr;
    } 

    //use the strategy
      public Object applyBuisnessRule(String jobcode) {

            try {
                Object = buisnessRuleName.execute(jobcode);
            } catch (Exception e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }

        return Object;
      }

}

Answer 1

如果您希望相同类型的对象作为参数：

interface ApplyBusinessRule<T> {
    public T execute(T jobCode) throws Exception;
}

^{*请注意更正后的界面名称。}

如果您想要不同类型的对象作为参数：

interface ApplyBusinessRule<T, R> {
    public R execute(T jobCode) throws Exception;
}

这类似于Java 8定义的Function接口：

@FunctionalInterface
public interface Function<T, R> {
    R apply(T t);
}

要了解详情，请阅读The Java™ Tutorials。

将对象作为参数传递并获取对象作为回报

1 个答案: