所以我有两列看起来像这样:
V1 V2
ENSP00000222573_N559D ENSG00000105855
ENSP00000222573_N559D ENSG00000105855
ENSP00000267853_E337* ENSG00000108239
ENSP00000299441_R1672P,R1672G ENSG00000127415
ENSP00000334642_K277N. ENSG00000134324
ENSP00000342952_N585R ENSG00000134324
首先,我需要第一列提取_之后的所有字母/符号 所以结果需要看起来像这样:
V1 V2
ND ENSG00000105855
ND ENSG00000105855
E* ENSG00000108239
RP,RG ENSG00000127415
KN ENSG00000134324
NR ENSG00000134324
然后我想过滤这样只有当V1和... V2一起加倍,它们被过滤掉了。 所以最终结果将是:
V1 V2
ND ENSG00000105855
E* ENSG00000108239
RP,RG ENSG00000127415
KN ENSG00000134324
NR ENSG00000134324
答案 0 :(得分:2)
使用tidyverse的解决方案。 dat2
是最终输出。
library(tidyverse)
dat2 <- dat %>%
separate(V1, into = c("Re", "V1"), sep = "_") %>%
select(-Re) %>%
mutate(V1 = str_replace_all(V1, "[0-9]*", "")) %>%
distinct(V1, V2, .keep_all = TRUE)
dat2
# V1 V2
# 1 ND ENSG00000105855
# 2 E* ENSG00000108239
# 3 RP,RG ENSG00000127415
# 4 KN. ENSG00000134324
# 5 NR ENSG00000134324
数据强>
dat <- read.table(text = "V1 V2
ENSP00000222573_N559D ENSG00000105855
ENSP00000222573_N559D ENSG00000105855
'ENSP00000267853_E337*' ENSG00000108239
'ENSP00000299441_R1672P,R1672G' ENSG00000127415
'ENSP00000334642_K277N.' ENSG00000134324
ENSP00000342952_N585R ENSG00000134324",
header = TRUE, stringsAsFactors = FALSE)
答案 1 :(得分:1)
选项可以使用sapply
和strsplit
作为:
sapply(df, function(x){
sapply(strsplit(x, split = "_"), function(y){
if(length(y)<2){
y
} else {
gsub("[0-9]+","",y[2])
}
})
}) %>% as.data.frame() %>% distinct()
# V1 V2
# 1 ND ENSG00000105855
# 2 E* ENSG00000108239
# 3 RP,RG ENSG00000127415
# 4 KN. ENSG00000134324
# 5 NR ENSG00000134324
数据:强>
df <- read.table(text =
"V1 V2
ENSP00000222573_N559D ENSG00000105855
ENSP00000222573_N559D ENSG00000105855
ENSP00000267853_E337* ENSG00000108239
ENSP00000299441_R1672P,R1672G ENSG00000127415
ENSP00000334642_K277N. ENSG00000134324
ENSP00000342952_N585R ENSG00000134324",
stringsAsFactors = FALSE, header = TRUE)