Question

我想保存表单中的数据，然后单击“添加”按钮返回上一页。它显示出一些错误。任何人都可以建议正确的方法吗？

template.html

  <div class="panel panel-default">
  <div class="panel-heading">
    <h3 class="panel-title">Add your own Category </h3>
  </div>
  <div class="panel-body">
    <form method="POST" class="post-form">
      {% csrf_token %}
      {{ form.as_p }}

                    </div>
                      </div>
                    </div>
        <input type="hidden" name="next" value="{{ request.path }}">
       <button type="submit" class="save btn btn-default" >Add</button>
    </form>

views.py

class CustomCategory(LoginRequiredMixin,CreateView):
    model = Category

   form_class = CategoryForm

   def form_valid(self, form):
    obj = form.save(commit=False)

   def category(request):
    next = request.POST.get('next', '/')
    return render (request,HttpResponseRedirect(next))

Answer 1

而不是增加重定向为形式的元件，的为什么不＆＃39;吨使用视图上的success_url字段，或者如果你需要去URL依赖的对象上，使用在所述get_success_url方法查看？

https://docs.djangoproject.com/en/2.0/ref/class-based-views/mixins-editing/

回到django的上一页

1 个答案: