valgrind显示strtok的错误,内存很大

时间:2018-05-23 15:32:14

标签: c valgrind strtok

我写了一个简单的代码,它将一个非常大的文件读入内存。 (该文件大小约为480兆字节)。该文件包含一些逗号分隔值0和1。代码非常简单。我首先得到文件大小,然后分配足够的缓冲区空间,读取文件,用逗号分隔,然后将其放入数组中。该计划如下:

 #include <stdio.h> 
 #include <stdlib.h>
 #include <string.h>

 int main(){
    long no_of_houses = 1048576L; //dimensions of my final table.
    int no_of_appliances = 5;
    int no_of_sectors = 48;

    int* intended_schedule; // this is where the table will be stored. 

    intended_schedule = (int*) malloc(no_of_houses * no_of_appliances * no_of_sectors * sizeof(int));

    FILE* fptr = fopen("./data/houses.csv", "r"); //this file is around 480 mega bytes.
    if(fptr == NULL){
            perror("housese file");
            exit(0);
    }

    fseek(fptr, 0L, SEEK_END); //find the size of the file before allocating space
    long size = ftell(fptr);
    rewind(fptr);

    char* buffer = (char*) calloc(1, size); //now we know the size, we can allocate space. 
    fread(buffer, size, 1, fptr);


    char* token = strtok(buffer, ",\n"); //it's a comma separated file. So break from comma
    long no = 0;
    while(token != NULL){
            if(no == no_of_houses*no_of_appliances*no_of_sectors)
                    break; //guard against unexpectedly big data file. 
            intended_schedule[no] = token[0] - 48;// it's either 0 or 1. So this is good enough
            no++;
            token = strtok(NULL, ",\n");
    }
    fclose(fptr);

    free(intended_schedule);
    free(buffer);

    return 0;
}

我使用此代码作为更大程序的函数,因为它给了我错误,我通过valgrind运行了这个程序。这是我得到的结果:

 goodman@node2 analyse_code]$ valgrind ./analyse
 ==39263== Memcheck, a memory error detector
 ==39263== Copyright (C) 2002-2017, and GNU GPL'd, by Julian Seward et al.
 ==39263== Using Valgrind-3.13.0 and LibVEX; rerun with -h for copyright info
 ==39263== Command: ./analyse
 ==39263==
 ==39263== Warning: set address range perms: large range [0x51f8040, 0x411f8040) (undefined)
 ==39263== Warning: set address range perms: large range [0x59e3f040, 0x77e3f040) (defined)
 ==39263== Warning: set address range perms: large range [0x59e3f040, 0x77e3f040) (defined)
 ==39263== Invalid read of size 1
 ==39263==    at 0x4EBEDCC: strtok (in /usr/lib64/libc-2.17.so)
 ==39263==    by 0x400997: main (analyse.c:36)
 ==39263==  Address 0x77e3f040 is 0 bytes after a block of size 503,316,480 alloc'd
  ==39263==    at 0x4C2B9B5: calloc (vg_replace_malloc.c:711)
  ==39263==    by 0x400904: main (analyse.c:27)
  ==39263==
  ==39263== Invalid read of size 1
  ==39263==    at 0x4EBEDFC: strtok (in /usr/lib64/libc-2.17.so)
  ==39263==    by 0x400997: main (analyse.c:36)
  ==39263==  Address 0x77e3f040 is 0 bytes after a block of size 503,316,480 alloc'd
  ==39263==    at 0x4C2B9B5: calloc (vg_replace_malloc.c:711)
  ==39263==    by 0x400904: main (analyse.c:27)
  ==39263==
  ==39263== Warning: set address range perms: large range [0x51f8028, 0x411f8058) (noaccess)
  ==39263== Warning: set address range perms: large range [0x59e3f028, 0x77e3f058) (noaccess)
  ==39263==
  ==39263== HEAP SUMMARY:
  ==39263==     in use at exit: 0 bytes in 0 blocks
  ==39263==   total heap usage: 3 allocs, 3 frees, 1,509,950,008 bytes allocated
  ==39263==
  ==39263== All heap blocks were freed -- no leaks are possible
  ==39263==
  ==39263== For counts of detected and suppressed errors, rerun with: -v
  ==39263== ERROR SUMMARY: 2 errors from 2 contexts (suppressed: 0 from 0)

我想知道为什么我会收到这些错误。据我所知,我的代码没有问题。是因为我的数据太大了吗?我不认为可能是这种情况,因为我在具有128 GB RAM的服务器上运行此代码。

任何帮助将不胜感激。

- ppgoodman

1 个答案:

答案 0 :(得分:1)

strtok()假定以NUL结尾的字符串,您的缓冲区 NOT NUL终止,因此strtok()将尝试超越缓冲区的末尾。但是你可以不用strtok()和大缓冲区。

您不需要来缓冲整个文件;对于像这样的简单情况,您可以使用单字符缓冲区逐步执行它。这将消耗更少的内存,并且也会更快(至少 2次)

 #include <stdio.h> 
 #include <stdlib.h>
 #include <string.h>

 int main(){
    unsigned long no_of_houses = 1048576L; //dimensions of my final table.
    unsigned int no_of_appliances = 5;
    unsigned int no_of_sectors = 48;
    unsigned long no = 0;
    int ch;
    unsigned int *intended_schedule; // this is where the table will be stored. 

    intended_schedule = malloc(no_of_houses * no_of_appliances * no_of_sectors * sizeof *intended_schedule);

    FILE *fptr = fopen("./data/houses.csv", "r"); //this file is around 480 mega bytes.
    if(!fptr) {
            perror("housese file");
            exit(0);
    }

    while(no < no_of_houses*no_of_appliances*no_of_sectors) {
            ch = getc(fptr);
            if (ch== EOF) break;
            if (ch== '\n') continue;
            if (ch== ',') continue; 

            intended_schedule[no++] = ch - '0'; // it's either 0 or 1. So this is good enough
    }
    fclose(fptr);

    free(intended_schedule);

    return 0;
}