Question

这不应该让我感到困惑，但我希望能够解决这个问题：

array:3 [▼
  "subject" => array:2 [▼
        0 => "math"
        1 => "english"
  ]
 "grade" => array:2 [▼
      0 => "a"
      1 => "b"
  ]
  "received" => array:2 [▼
      0 => "2017"
      1 => "2016"
  ]
]

进入这个：

array:2 [▼
  "0" => array:3 [▼
    "subject" => "math"
    "grade" => "a"
    "received" => "2017"
  ]
  "1" => array:3 [▼
    "subject" => "english"
    "grade" => "b"
    "received" => "2016"
  ]
]

尝试以几种不同的方式循环，但似乎永远不会得到我想要的结果，任何帮助都会非常感激！

Answer 1

$keys = array_keys($array);
$result = array_map(
    function (...$values) use ($keys) { return array_combine($keys, $values); }, 
    ...array_values($array)
);

本质上是这个，但重复性较低：

array_map(
    function ($subject, $grade, $received) {
        return [
            'subject' => $subject,
            'grade' => $grade, 
            'received' => $received
        ];
    },
    $array['subject'],
    $array['grade'],
    $array['received']
)

有关详细说明，请参阅array_map手册和...。

Answer 2

简单版本：

$arr1 = array(...);
$arr2 = array();

foreach ($arr1 as $k => $v) {
    foreach ($v as $x => $y) {
        $arr2[$x][$k] = $y;
    }
}

但是你应该添加条件，如果数组元素不存在，创建它，或者你可能会得到错误，具体取决于你的PHP配置。

PHP数组结构改变

2 个答案: