我需要使用balebot python SDK向一组草捆用户发送短信。我想直接发送它们,并且不想等待它们与我的机器人开始对话。我有他们的user_id和access_hash。我已尝试过这段代码,但我遇到了一个' HIT_LIMIT'错误。
BotErrorResponse {_id:' 1001',_body:{code:403,tag: ' HIT_LIMIT',data:{},retryIn:null},代码:403,tag: ' HIT_LIMIT',data:{},retryIn:null}
我使用for循环再次使用time.sleep()发送它们但是当我使用此sendMessage
函数时无效!
代码
def success(response, user_data):
print("success : ", response)
print(user_data)
def failure(response, user_data):
print("failure : ", response)
print(user_data)
def send_message(bot, update):
for peer in save_peers:
bot.send_message(TextMessage("Text"), Peer(peer_type=PeerType.user, peer_id=peer["id"],
access_hash=peer["accessHash"]),
success_callback=success, failure_callback=failure)
time.sleep(2)
答案 0 :(得分:3)
这是因为asyncio和time.sleep()不匹配。如果我是你,我会使用asyncio.get_event_loop()而不是for循环和time.sleep()。 这是一个示例代码:
save_peers = [{"$type": "User", "id": 128521332, "accessHash": "9256310829016723727"},
{"$type": "User", "id": 928571821, "accessHash": "4540300829906797423"}
]
limit_message = 50000
bot_send_delay = 2
my_send_loop = asyncio.get_event_loop()
my_send_loop2 = asyncio.get_event_loop()
def send_message(bot, how_many, message_number, loop):
print("sending for ", message_number, " st time")
my_send_loop2.call_soon(send_message2, bot, len(save_peers), 0, my_send_loop2)
if message_number < how_many:
loop.call_later(bot_send_delay, send_message, bot, how_many, message_number + 1, loop)
else:
print("index finished")
def send_message2(bot, top, down, loop):
print("sending for ", down, " st time")
if down < top:
bot.send_message(TextMessage("TEXT"), Peer(peer_type=PeerType.user, peer_id=save_peers[down]["id"],
access_hash=save_peers[down]["accessHash"]),
success_callback=success, failure_callback=failure)
loop.call_later(bot_send_delay, send_message2, bot, top, down + 1, loop)
my_send_loop.call_soon(send_message, bot, limit_message, 0, my_send_loop)
updater.run()