Question

如何告诉Java打印随机生成的匹配数字的值。例如，如果输出为3,3,7：系统应该打印出来，＆＃34;你有两个3＆＃34;。

    int r1 = (int) (Math.random()*6) +1;
    int r2 = (int) (Math.random()*6) +1;
    int r3 = (int) (Math.random()*6) +1;


    System.out.print("Your numbers are " + r1 + r2 + r3);

    if (r1 == r2 && r2 ==r3 )
        System.out.print(": You got all" + r1 + "'s");
    else if (r1 == r2 || r2 == r3 || r1 == r3)
        System.out.print(": You got two" + "'s");
    else if (r1 != r2 && r2 != r3)
        System.out.print(": NO MATCHES!");
    else {

    }

Answer 1

使用Collections.frequency方法处理任意数量的卷的解决方案是：

List<Integer> list = Arrays.asList(roll1, roll2, roll3);
Set<Integer> set = new HashSet<Integer>(list);

for (Integer i : set)
{
    System.out.println(i + ": " + Collections.frequency(list, i));
}

将您的卷转换为列表，制作一组（一组没有重复的条目）。

对于集合中的每个值，列表中的值存在的频率。对于卷3, 3, 7，这将打印：

3: 2
7: 1

Answer 2

你应该清理你的代码......

您提供的代码无法编译。逻辑似乎没问题。

package stackoverflow;

public class main {

    public static void main(String[] args) {
        int r1 = (int) (Math.random()*6) +1;
        int r2 = (int) (Math.random()*6) +1;
        int r3 = (int) (Math.random()*6) +1;


        System.out.print("Your numbers are " + r1 + r2 + r3);

        if (r1 == r2 && r2 ==r3 )
            System.out.print(": You got all " + r1 + "'s");
        else if (r1 == r2 || r2 == r3 || r1 == r3)
            System.out.print("numbers: " + r1 + " " + r2 + " " + r3);
        else if (r1 != r2 && r1 != r3) 
            System.out.print(": NO MATCHES!");
        else {

        }
    }
}

这应该基于您给定的代码。

请注意，您正在命名不一致/存在的变量。

Answer 3

解决方案：将两个数字的随机分配数分成三部分。

int r1 = (int) (Math.random()*6) +1;
int r2 = (int) (Math.random()*6) +1;
int r3 = (int) (Math.random()*6) +1;


System.out.print("Your numbers are " + r1 + r2 + r3);

if (r1 == r2 && r2 ==r3 )
    System.out.print(": You got all" + r1 + "'s");
else if (r1 == r2)
    System.out.print(": You got two" + r1 + "'s");
else if (r2 == r3)
    System.out.print(": You got two" + r2 + "'s");    
else if (r1 == r3)
    System.out.print(": You got two" + r1 + "'s");
else if (r1 != r2 && r2 != r3)
    System.out.print(": NO MATCHES!");

Answer 4

最简单的事情是

    int roll1 = (int) (Math.random()*6) +1;
    int roll2 = (int) (Math.random()*6) +1;
    int roll3 = (int) (Math.random()*6) +1;


    System.out.print("Your numbers are " + roll1 + roll2 + roll3);

    if (roll1 == roll2 && roll2 == roll3 )
        System.out.print(": You got all" + s1 + "'s");
    else if (roll1 == roll2) 
        System.out.print(": You got two" + roll1 + "'s");
    else if (roll2 == roll3)
        System.out.print(": You got two" + roll2 + "'s");
    else if (roll1 == roll3)
        System.out.print(": You got two" + roll1 + "'s");
    else
        System.out.print(": NO MATCHES!");

比较答案（不在数组中）

4 个答案: