Question

我不完全确定如何使用这个json输出在python中列出它们，我的意思是循环它们并从JSON输出中收集信息？

JSON输出：https://hastebin.com/riroteqiso.json （从Ombi API收集的数据，使用Traktr作为提供者。）

代码段：

request_headers = {'apiKey': pmrs_api_token, 'content-type': 'application/json'}
        async with aiohttp.ClientSession() as ses:
            async with ses.get(pmrs_full_endpoint, headers=request_headers) as response:
                a = await response.json()
                for entry in (a['response']):
                    print(entry)

错误追溯：

Traceback (most recent call last):
  File "/home/sm/.local/lib/python3.6/site-packages/discord/ext/commands/core.py", line 50, in wrapped
    ret = yield from coro(*args, **kwargs)
  File "/home/sm/Programming/Python/Discord-Bots/Plex-bot/cogs/ombi.py", line 85, in populartv
    for entry in (a['response']):
TypeError: list indices must be integers or slices, not str

编辑：

通过改变它来解决这个问题，但是现在我还有另一个问题。

async with aiohttp.ClientSession() as ses:
        async with ses.get(pmrs_full_endpoint, headers=request_headers) as response:
            a = await response.json()
            for entry in a:
                b = await response.json()
                print(type(b)) # Outputs <class 'list'>
                title = (b[entry]['title'])
                first_aired = (b[entry]['firstAired'])
                desc = (b[entry]['overview'])

再次给我一个关于类型的错误......：/

Answer 1

你应该改变：

for entry in (a['response']):

人：

for entry in a:

Answer 2

这应该可以解决您的错误。您不需要新的b对象。＆＃39;条目＆＃39;变量将包含列表中的元素，在这种情况下，它将是列表中的字典对象。因此，您只需使用entry['title']提取值。

async with aiohttp.ClientSession() as ses:
    async with ses.get(pmrs_full_endpoint, headers=request_headers) as response:
        a = await response.json()
        for entry in a:
            title = entry['title']
            first_aired = entry['firstAired']
            desc = entry['overview']

如何使用Python提取JSON中的数据

2 个答案: