我从Google智能助理收到一个大型json,我想从中检索一些具体细节。 json如下:
{
"responseId": "************************",
"queryResult": {
"queryText": "actions_intent_DELIVERY_ADDRESS",
"action": "delivery",
"parameters": {},
"allRequiredParamsPresent": true,
"fulfillmentMessages": [
{
"text": {
"text": [
""
]
}
}
],
"outputContexts": [
{
"name": "************************/agent/sessions/1527070836044/contexts/actions_capability_screen_output"
},
{
"name": "************************/agent/sessions/1527070836044/contexts/more",
"parameters": {
"polar": "no",
"polar.original": "No",
"cardinal": 2,
"cardinal.original": "2"
}
},
{
"name": "************************/agent/sessions/1527070836044/contexts/actions_capability_audio_output"
},
{
"name": "************************/agent/sessions/1527070836044/contexts/actions_capability_media_response_audio"
},
{
"name": "************************/agent/sessions/1527070836044/contexts/actions_intent_delivery_address",
"parameters": {
"DELIVERY_ADDRESS_VALUE": {
"userDecision": "ACCEPTED",
"@type": "type.googleapis.com/google.actions.v2.DeliveryAddressValue",
"location": {
"postalAddress": {
"regionCode": "US",
"recipients": [
"Amazon"
],
"postalCode": "NY 10001",
"locality": "New York",
"addressLines": [
"450 West 33rd Street"
]
},
"phoneNumber": "+1 206-266-2992"
}
}
}
},
{
"name": "************************/agent/sessions/1527070836044/contexts/actions_capability_web_browser"
}
],
"intent": {
"name": "************************/agent/intents/86fb2293-7ae9-4bed-adeb-6dfe8797e5ff",
"displayName": "Delivery"
},
"intentDetectionConfidence": 1,
"diagnosticInfo": {},
"languageCode": "en-gb"
},
"originalDetectIntentRequest": {
"source": "google",
"version": "2",
"payload": {
"isInSandbox": true,
"surface": {
"capabilities": [
{
"name": "actions.capability.MEDIA_RESPONSE_AUDIO"
},
{
"name": "actions.capability.SCREEN_OUTPUT"
},
{
"name": "actions.capability.AUDIO_OUTPUT"
},
{
"name": "actions.capability.WEB_BROWSER"
}
]
},
"inputs": [
{
"rawInputs": [
{
"query": "450 West 33rd Street"
}
],
"arguments": [
{
"extension": {
"userDecision": "ACCEPTED",
"@type": "type.googleapis.com/google.actions.v2.DeliveryAddressValue",
"location": {
"postalAddress": {
"regionCode": "US",
"recipients": [
"Amazon"
],
"postalCode": "NY 10001",
"locality": "New York",
"addressLines": [
"450 West 33rd Street"
]
},
"phoneNumber": "+1 206-266-2992"
}
},
"name": "DELIVERY_ADDRESS_VALUE"
}
],
"intent": "actions.intent.DELIVERY_ADDRESS"
}
],
"user": {
"lastSeen": "2018-05-23T10:20:25Z",
"locale": "en-GB",
"userId": "************************"
},
"conversation": {
"conversationId": "************************",
"type": "ACTIVE",
"conversationToken": "[\"more\"]"
},
"availableSurfaces": [
{
"capabilities": [
{
"name": "actions.capability.SCREEN_OUTPUT"
},
{
"name": "actions.capability.AUDIO_OUTPUT"
},
{
"name": "actions.capability.WEB_BROWSER"
}
]
}
]
}
},
"session": "************************/agent/sessions/1527070836044"
}
这个大型json向我的后端返回用户的交付地址详细信息(这里我以亚马逊的NY位置详细信息为例)。因此,我想检索接近这个大型json末尾的location
字典。 location
详细信息也出现在此json的开头附近,但我想要专门检索第二个location
字典,该字典接近这个大json的末尾。
出于这个原因,我必须自己阅读这个json并手动测试这个大json中location
字典的一些可能的“路径”,最后发现我必须编写以下行来检索第二个location
字典:
location = json['originalDetectIntentRequest']['payload']['inputs'][0]['arguments'][0]['extension']['location']
因此,我的问题如下:是否有任何简洁的方法可以自动检索此大型json中第二个location
字典的父键和索引的“路径”?
因此,我希望在任何json中对location
字典的所有出现执行此操作的函数的输出的一般格式如下:
[["path" of first `location` dictionary], ["path" of second `location` dictionary], ["path" of third `location` dictionary], ...]
上面的json将是
[["path" of first `location` dictionary], ["path" of second `location` dictionary]]
因为{/ 1}}字典有两次出现
location
我在脑海中有关于StackOverflow(Python--Finding Parent Keys for a specific value in a nested dictionary)的相关帖子,但我不确定这些是否适用于我的问题,因为这些是嵌套字典中的父键,而这里我说的是父键和字典中带有嵌套字典和列表的索引。
答案 0 :(得分:1)
我通过使用递归搜索解决了这个问题
# result and path should be outside of the scope of find_path to persist values during recursive calls to the function
result = []
path = []
from copy import copy
# i is the index of the list that dict_obj is part of
def find_path(dict_obj,key,i=None):
for k,v in dict_obj.items():
# add key to path
path.append(k)
if isinstance(v,dict):
# continue searching
find_path(v, key,i)
if isinstance(v,list):
# search through list of dictionaries
for i,item in enumerate(v):
# add the index of list that item dict is part of, to path
path.append(i)
if isinstance(item,dict):
# continue searching in item dict
find_path(item, key,i)
# if reached here, the last added index was incorrect, so removed
path.pop()
if k == key:
# add path to our result
result.append(copy(path))
# remove the key added in the first line
if path != []:
path.pop()
# default starting index is set to None
find_path(di,"location")
print(result)
# [['queryResult', 'outputContexts', 4, 'parameters', 'DELIVERY_ADDRESS_VALUE', 'location'], ['originalDetectIntentRequest', 'payload', 'inputs', 0, 'arguments', 0, 'extension', 'location']]