Question

为什么这不起作用而是返回ValueError？我正在尝试从用户那里获得输入，然后根据用户的选择，呈现特定视图。如果我将return redirect()移回post function内，它确实有效。

class Choice(View):

        form_class = SomeForm
        template_name = 'app/object_form.html'

        def get(self,request,*args, **kwargs):

             form = self.form_class()
             return render (request, self.template_name, {'form':form})

        def post(self,request,*args,**kwargs):

             form = self.form_class(request.POST)
             if form.is_valid():
                 self.redirect_to_createform(request,form.cleaned_data['choice'])

             else:
                print('form not valid')
                print(form.errors)
                return render (request, self.template_name, {'form':form})

        def redirect_to_createform(self, request, option):

            print(option)
            ## Here i should have some logic to redirect to different views depending on the `option`
            return redirect('to_somewhere')

编辑 - 我理解错误的含义，但我如何实现上述目标。

Answer 1

您缺少返回声明，如下所示

        if form.is_valid():
           return self.redirect_to_createform(request,form.cleaned_data['choice'])

基于Django类的视图 - 返回HTTPResponse

1 个答案: