Question

您好我正在尝试将json文件插入mongoDb.I已编写代码并且对我来说工作正常。

＆＃13;

import sys, json, pymongo,glob
from pymongo import MongoClient
from bson import json_util
from multiprocessing.sharedctypes import template
from json.decoder import JSONDecodeError
from itertools import count


connection = MongoClient('localhost',27017)
db = connection.Mysample
mycollection = db.Mynewsample
folder = 'C:/ESRILKA/Cloud Team/Tmobile/JSON To CSV  Files/JSON files/*.json'
jsonFiles = glob.glob(folder)
for file in jsonFiles:
    with open(file) as template:
                      
                try:                
                    template_dct=json.load(template)
                    result = db.Mynewsample.insert_one(template_dct)                    
                    print('Inserted post id %s ' % result.inserted_id)
                    
                except (ValueError, KeyError, TypeError) as e:
                        print("Invalid json at")
                        pass

＆＃13;

但是现在我想在插入之前验证json文件。如果json无效，它应该显示一条消息说＆＃34;解析失败等等。＆＃34;

Answer 1

使用try，除外。一个例子：

import json


def is_valid_json(json_string):
    try:
        json.loads(json_string)
    except:
        return False
    return True


# Return True
print(is_valid_json('{"name": "Jhon"}'))

# Return False
print(is_valid_json("{'name': 'Jhon'}"))

Demo

Python：当我尝试将JSON文件插入Mongodb时，如果json文件无效，则抛出error.how来捕获错误

1 个答案: