实际上，我想以json的形式将用户电话的联系人发送到服务器。我读到的某个地方，它可以通过GSON库完成，但我无法获得确切的代码。电话号码和联系人姓名是字符串形式。我曾经尝试过两门课。
一个是主类，我在其中获取联系人
public class Access_contacts extends AppCompatActivity {
ArrayList<Contact_Pojo> arrayList;
private static final int PERMISSION_REQUEST_CONTACT =123 ;
private static final int PICK_CONTACT =147 ;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_access_contacts);
arrayList= new ArrayList<Contact_Pojo>();
askForContactPermission();
Gson gson = new Gson();
Type type = new TypeToken<List<Contact_Pojo>>() {}.getType();
String json = gson.toJson(arrayList, type);
ArrayList<Contact_Pojo> fromJson = gson.fromJson(json, type);
for (Contact_Pojo task : fromJson) {
System.out.println(task);
}
}
private void gettingPhoneContacts() {
ContentResolver cr = getApplicationContext().getContentResolver();
// Read Contacts
Cursor c = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, new String[] { ContactsContract.Contacts._ID,
ContactsContract.Contacts.DISPLAY_NAME, ContactsContract.CommonDataKinds.Phone.NUMBER,
ContactsContract.RawContacts.ACCOUNT_TYPE }, ContactsContract.RawContacts.ACCOUNT_TYPE + " <> 'google' ",
null, null);
if (c.getCount() <= 0) { Toast.makeText(getApplicationContext(), "No Phone Contact Found..!",
Toast.LENGTH_SHORT).show(); }
else {
while (c.moveToNext()) {
String Phone_number = c .getString(c .getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER)); //Phone number
String name = c .getString(c .getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
arrayList.add(new Contact_Pojo(name,Phone_number));
Log.d("contactsss",Phone_number+ " "+name);
//Name of contact
}
for(int i=0;i<arrayList.size();i++)
{
Log.d("jopo",""+arrayList.get(i));
}
}}
private void askForContactPermission() {
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
if (ContextCompat.checkSelfPermission(Access_contacts.this,Manifest.permission.READ_CONTACTS) != PackageManager.PERMISSION_GRANTED) {
// Should we show an explanation?
if (ActivityCompat.shouldShowRequestPermissionRationale(Access_contacts.this,
Manifest.permission.READ_CONTACTS)) {
AlertDialog.Builder builder = new AlertDialog.Builder(Access_contacts.this);
builder.setTitle("Contacts access needed");
builder.setPositiveButton(android.R.string.ok, null);
builder.setMessage("please confirm Contacts access");//TODO put real question
builder.setOnDismissListener(new DialogInterface.OnDismissListener() {
@TargetApi(Build.VERSION_CODES.M)
@Override
public void onDismiss(DialogInterface dialog) {
requestPermissions(
new String[]
{Manifest.permission.READ_CONTACTS}
, PERMISSION_REQUEST_CONTACT);
}
});
builder.show();
// Show an expanation to the user *asynchronously* -- don't block
// this thread waiting for the user's response! After the user
// sees the explanation, try again to request the permission.
} else {
// No explanation needed, we can request the permission.
ActivityCompat.requestPermissions(Access_contacts.this,
new String[]{Manifest.permission.READ_CONTACTS},
PERMISSION_REQUEST_CONTACT);
// MY_PERMISSIONS_REQUEST_READ_CONTACTS is an
// app-defined int constant. The callback method gets the
// result of the request.
}
}else{
getContact();
}
}
else{
getContact();
}
}
private void getContact() {
Intent intent = new Intent(Intent.ACTION_PICK, ContactsContract.Contacts.CONTENT_URI);
startActivityForResult(intent, PICK_CONTACT);
}
@Override
public void onRequestPermissionsResult(int requestCode,
String permissions[], int[] grantResults) {
switch (requestCode) {
case PERMISSION_REQUEST_CONTACT: {
// If request is cancelled, the result arrays are empty.
if (grantResults.length > 0
&& grantResults[0] == PackageManager.PERMISSION_GRANTED) {
gettingPhoneContacts();
// permission was granted, yay! Do the
// contacts-related task you need to do.
} else {
Toast.makeText(this, "No Permission for Contacts", Toast.LENGTH_SHORT).show();
// permission denied, boo! Disable the
// functionality that depends on this permission.
}
return;
}
// other 'case' lines to check for other
// permissions this app might request
}
}
}
其他是POJO类，如下：
public class Contact_Pojo {
@Override
public String toString() {
return "Contact_Pojo [name=" + name + ", number=" + number + " ]";
}
public Contact_Pojo(String name, String number) {
this.name = name;
this.number = number;
}
String name,number;;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getNumber() {
return number;
}
public void setNumber(String number) {
this.number = number;
}
}
答案 0 :(得分：1)
这是解决方案。你必须决定＆＃34;你需要什么？＆＃34; JSONOject或JSONArray。 在顶部声明。
JSONObject mainObject = new JSONObject();
JSONArray jsonBody;
现在在OnCreate中
jsonBody = new JSONArray();
try {
JSONObject object_1 = new JSONObject();
object_1.put("KEY_VALUE", KEY_PAIR);
object_1.put("KEY_VALUE", KEY_PAIR);
object_1.put("KEY_VALUE", KEY_PAIR);
object_1.put("KEY_VALUE", KEY_PAIR);
object_1.put("KEY_VALUE", KEY_PAIR_id);
jsonBody.put(0, object_1);
mainObject.put("data", jsonBody);
String data = mainObject.toString();
} catch (Exception e) {
e.printStackTrace();
}
在KEY_PAIR中添加键代替KEY_VALUE及其值。
如果需要发送JSONArray传递jsonBody，如果需要JSONObject则使用mainObject。
答案 1 :(得分：0)
我认为您应该使用JSONObject和JSONArray，如：
JSONArray array = new JSONArray("Catalo");
JSONObject contact = new JSONObject();
contact.put("key", "value");
contact.put("key", "value");
...
array.put(contact);