Sscanf不会以相同的方式读取相同的线条

时间:2018-05-22 22:06:40

标签: c scanf

#include <stdlib.h>

void printLine(char* line) {
     char lat, lon;
     unsigned int year, month, day;
     float temp, uncertainty, latitude, longitude;
     char country[100], city[100];
     int result;

     result = sscanf(line, "%u-%u-%u,%f,%f,%[^,],%[^,],%f%c,%f%c", &year,
         &month,&day, &temp, &uncertainty, city, country, &latitude, &lat, &longitude, &lon);

     printf("%u-%u-%u,%f,%f,%s,%s,%f%c,%f%c\n", year, month, day, temp, uncertainty,
         city, country, latitude, lat, longitude, lon);

     printf("sscanf read %i variables\n", result);
}
int main() {
    char line[] = "2013-08-01,19.005,3.621,Addis Abeba,Ethiopia,8.84N,38.11E";
    char line2[] = "1816-03-01,27.426,1.793,Bangkok,Thailand,13.66N,99.91E";
    char line3[] = "1743-11-01,3.264,1.665,New York,United States,40.99N,74.56W";

    printLine(line);
    printLine(line2);
    printLine(line3);
}

它读取的某些行正确,而某些行则不读取最后一个字符。我不确定导致这个bug的原因,我可能会调用某种未定义的行为,但我不确定它是什么。

1 个答案:

答案 0 :(得分:2)

如评论中所述,E正在被视为浮动的一部分。您可以使用此代码将float读取为字符串,然后将其转换为float:

void printLine(char* line) {
    char lat, lon;
    unsigned int year, month, day;
    float temp, uncertainty;
    char latitude[100], longitude[100];
    float latFloat, longFloat;
    char country[100], city[100];
    char blah[100];
    int result;
    result = sscanf(line, "%u-%u-%u,%f,%f,%[^,],%[^,],%[0-9.]%c,%[0-9.]%c", &year,
        &month, &day, &temp, &uncertainty, city, country, latitude, &lat, longitude, &lon);

    latFloat = atof(latitude);
    longFloat = atof(longitude);

    printf("%u-%u-%u,%f,%f,%s,%s,%f%c,%f%c\n", year, month, day, temp, uncertainty,
        city, country, latFloat, lat, longFloat, lon);

    printf("sscanf read %i variables\n", result);
}