Question

我有一个小问题：如果我通过网络上的php向我的Android设备发送通知，则会建立通知，但不会在应用程序外振动。当我进入应用程序时，它只会振动。

以下是我的代码：

PHP：

//disordered products.
var products = [{
    primaryName: 'test'
  },

  {
    name: 'test7'
  },
  {
    primaryName: 'test3'
  },
  {
    name: 'test4'
  },
  {
    name: 'test5'
  },
  {
    primaryName: 'test1'
  },
  {
    primaryName: 'test2'
  },

  {
    name: 'test6'
  },
]
var filtered = products.map(function(product) {
    var universalName = product['primaryName'] || product['name'];
    product.universalName = universalName;
    return product;
  })
  .sort(function(a, b) {
    return a['universalName'].localeCompare(b['universalName']);
  });

//ordered by universalName;
console.log(filtered);

我的Android通知代码：

function  send_notification ($token, $message, $Raum, $Notruf){
        $url = 'https://fcm.googleapis.com/fcm/send';
        $fields = array('to' => $token, 'notification' => array('body' => "Raum ".$Raum.", Notruf ".$Notruf), 'data' => array ('message' => $message));
        $headers = array ('Authorization:key = (HERE IS MY AUTH KEY)','Content-Type: application/json');

        $ch = curl_init ();
        curl_setopt($ch, CURLOPT_URL, $url);
        curl_setopt($ch, CURLOPT_POST, true);
        curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
        curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
        curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
        curl_setopt($ch, CURLOPT_IPRESOLVE, CURL_IPRESOLVE_V4);
        curl_setopt($ch, CURLOPT_POSTFIELDS, json_encode($fields));
        $result = curl_exec($ch);
        if ($result == FALSE) {
            die ('Curl failed: ' . curl_error($ch));
        }
        curl_close($ch);
        return $result;
    }

        $sql = 'SELECT token FROM devices as d, Sani as s WHERE d.sean = s.sean AND s.Status!=0';

    $result = mysqli_query($db, $sql);
    $tokens = array ();

    if (mysqli_num_rows($result) > 0) {
        while ($row = mysqli_fetch_assoc($result)){
            $tokens[] = $row["token"];
        }
    }

    mysqli_close($db);

    $message = array ("message" => "Raum ".$Raum.", Notruf ".$Notruf);
    for ($i = 0; $i < count($tokens); ++$i) {
        $message_status = send_notification ($tokens[$i], $message, $Raum, $Notruf);
        echo $message_status;
    }

我无法在线获得任何修复，所以我在这里问。我怎么说，振动是有效的，但只在应用程序内部。如果我关闭它，即使没有停止过程，它也只显示通知，不会振动或显示正确的徽标。

When inside the app the notification looks like this (vibrating and icon showing):

When outside the app the notification looks like this (not vibrating and icon not showing):

Android应用程序不会在应用程序外振动

0 个答案: