import datetime
import re
import pymongo
from datetime import timedelta, date
def daterange(d, d1):
for n in range(int ((d1 - d).days)):
yield d + timedelta(n)
#conect bd
uri = "mongodb://127.0.0.1:27017"
client = pymongo.MongoClient(uri)
database = client['db']
collection = database['currency']
d = input('Insert beginning date (yyyy-mm-dd): ')
d1 = input('Insert end date (yyyy-mm-dd): ')
#search bd
item = collection.find_one({"date" : d})
item1 = collection.find_one({"date" : d1})
d = collection.find_one({})
d1 = collection.find_one({})
datas = item['date']
datas1 = item1['date']
#conversão de string para objecto
dataObject = datetime.datetime.strptime(datas, "%Y-%m-%d")
dataObject1 = datetime.datetime.strptime(datas1, "%Y-%m-%d")
#range
for single_date in daterange(dataObject, dataObject1):
print (single_date.strftime("%Y-%m-%d"))
如果可能,我想将此代码的输出变为var列表。 例如,开始日期为2018-05-07,结束日期为2018-05-11,输出为:
2018-05-07
2018-05-08
2018-05-09
2018-05-10
如何将其添加到变量中?
答案 0 :(得分:3)
假设此部分在列表中生成您想要的日期:
#range
for single_date in daterange(dataObject, dataObject1):
print (single_date.strftime("%Y-%m-%d"))
将其更改为:
mylist = []
#range
for single_date in daterange(dataObject, dataObject1):
mylist.append(single_date.strftime("%Y-%m-%d"))
答案 1 :(得分:3)
这比简单的for循环语句
更快my_list = [d.strftime("%Y-%m-%d") for d in daterange(dataObject, dataObject1)]