Question

我有一个如下数组：

let totalArr = ["First","Second","Third","Fourth","First","Second", "Second"]

我的要求输出是：

let grouper = [["First","First"],["Second", "Second", "Second"],["Third"],  ["Fourth"]]

任何人都可以进行最佳迭代吗？

Answer 1

试试这个：）

您可以将任何String数组传递给该函数，它将返回您想要的结果：

func groupArr(totalArr: [String]) -> [Any]{
    var grouperArr = [[String]]()
    for i in totalArr{
        let arr = totalArr.filter({($0 == i)}) as [String]
        if(grouperArr.contains(arr) == false){
            grouperArr.append(arr)
        }
    }
    return grouperArr
}

Answer 2

 let totalArr = ["First","Second","Third","Fourth","First","Second", "Second"]

 let grouper =   (Dictionary(grouping: totalArr, by: { $0})).map {  $0.value}

 print(grouper)

或

let arranged = (Dictionary(grouping: totalArr, by: { $0})).values print(arranged)

Answer 3

您可以使用Dictionay的分组功能创建一个组，然后获取所有值。

let totalArr = ["First","Second","Third","Fourth","First","Second", "Second"]

let group = Dictionary(grouping: totalArr) { (object) -> String in
    let lowerBound = String.Index(encodedOffset: 0)
    let upperBound = String.Index(encodedOffset: 1)
    return String(object[lowerBound...upperBound])
}
print("group :\(group.values)")

Answer 4

迅速5：

extension Array {
    func chunked(into size: Int) -> [[Element]] {
        return stride(from: 0, to: count, by: size).map {
            Array(self[$0 ..< Swift.min($0 + size, count)])
        }
    }
}

如何使用它：

let numbers = Array(1...100)
let result = numbers.chunked(into: 5)

Source

在swift 3中将数组对象拆分为数组

4 个答案: