如何使用pywinauto获取特定的系统托盘图标？

Question

例如来自通知区域的Slack图标：

如果出现“隐藏”图标选项，我们如何获得特定图标？

Answer 1

这对我有用，

如果您的应用图标在任务栏上可见

app = Application(backend="uia").connect(path="explorer.exe")
sys_tray = app.window(class_name="Shell_TrayWnd")
sys_tray.child_window(title=<your icon>).click()

隐藏托盘中的案例应用程序图标

app = Application(backend="uia").connect(path="explorer.exe")
st = app.window(class_name="Shell_TrayWnd")
t = st.child_window(title="Notification Chevron").wrapper_object()
t.click()

# Handle notify icon  overflow window

list_box = Application(backend="uia").connect(class_name="NotifyIconOverflowWindow")
list_box_win = list_box.window(class_name="NotifyIconOverflowWindow")
list_box_win.wait('visible', timeout=30, retry_interval=3)

# Select required option from drop-down 

ddm = desk.create_window(best_match="DropDownMenu")
desk.wait_for_window_to_appear(ddm, wait_for='ready', timeout=20, retry_interval=2)
ddm.child_window(title=<select option>, control_type="MenuItem").click_input()

Answer 2

使用此代码（已修改的sunil-kumar代码）

from pywinauto import Application
import time

app = Application(backend="uia").connect(path="explorer.exe")
st = app.window(class_name="Shell_TrayWnd")
t = st.child_window(title="Notification Chevron").wrapper_object()
t.click()

time.sleep(0.25)

list_box = Application(backend="uia").connect(class_name="NotifyIconOverflowWindow")
list_box_win = list_box.window(class_name="NotifyIconOverflowWindow")
list_box_win.wait('visible', timeout=30, retry_interval=3)

list_box_win.child_window(title="APPLICATION NAME").click()