Question

我有generic class view，我正试图在def view_events (request): template ='appform/view_events.html' items = Event.objects.filter(owner=request.user) pages = pagination(request,items, num = 10) print(pages) context = { 'items': pages[0], 'page_range': pages[1], } return render(request, template, context)中对其进行转换：

原件：

class ViewEvents(generic.ListView):

    template_name = 'app/view_events.html'
    model = Event
    context_object_name = 'events'
    pagination = ???

    def get_queryset(self):

        return Event.objects.filter(owner = self.request.user)

通用类视图：

generic class view

编辑：我已经使用this作为分页，这是一个自定义分页符。我想问的问题是如何在

class ViewEvents(generic.ListView):

    template_name = 'app/view_events.html'
    model = Event
    context_object_name = 'items'

    def get_queryset(self):

        return Event.objects.filter(owner = self.request.user)


    def get_context_data(self, **kwargs):

        context = super(ViewEvents, self).get_context_data(**kwargs)
        objects_all = Event.objects.filter(owner = self.request.user)
        pages = pagination(self.request, objects_all, num = 10)
        context['items'] = pages[0]
        context['page_range'] = pages[1]

        return  context

中实现它？

后来编辑：这使它运作起来，以防它可能对某人有用：）

ValueError: Shape of passed values is (20, 32), indices imply (20, 38)

Django - 从功能视图到泛型类视图

0 个答案: