对不起，我是noob T.T
import numpy as np
import json
import ast
import itertools
data1 = b'[{"id":"1","array1_1":"0","array1_2":"1","array2_1":"2","array2_2":"3","array3_1":"44","array3_2":"55"},{"id":"asd","array1_1":"234","array1_2":"[[0, 26, 60, 45], [0, -45, 45]]","array2_1":"[[23, 345], [543, 321]]","array2_2":"jytj","array3_1":"5","array3_2":"6"},{"id":"bb","array1_1":"bbb","array1_2":"ad","array2_1":"[[23, 345], [543, 321]]","array2_2":"[[0, 45], [45]]","array3_1":"[[34, 45], [66, 88]]","array3_2":"sfw"},{"id":"aa","array1_1":"aa","array1_2":"[[0, 26, 60, 45], [0, -45, 45]]","array2_1":"gfd","array2_2":"[[0, 45], [45]]","array3_1":"sdf","array3_2":"[[26, 60], [0], [56, 34, 45]]"},{"id":"ss","array1_1":"00","array1_2":"[[0, 45], [0, -45, 45], [0, -45, 45, -26]]","array2_1":"[[31, 233], [152, 151], [190, 204], [205, 87], [231, 48], [255, 194]]","array2_2":"[[0, 45], [45], [45], [26, 45, 63], [45], [0, 26, 45, 63]]","array3_1":"[[29, 194], [32, 234], [165, 229], [232, 46], [258, 190]]","array3_2":"[[45], [0, 45], [0, 26, 45], [0, -63, 45, 63], [0, 26, 45]]"}]'
data2 = data1.decode()
data3 = {"key" : [data2]}
s = json.dumps(data3)
data4 = str.encode(s)
data5 = json.loads(data4)
data6 = data5['key']
data7 = data6[0]
data8 = ast.literal_eval(data7)
d0 = [d['id']for d in data8]
d1 = [d['array1_1']for d in data8]
d2 = [d['array1_2']for d in data8]
d3 = [d['array2_1']for d in data8]
d4 = [d['array2_2']for d in data8]
d5 = [d['array3_1']for d in data8]
d6 = [d['array3_2']for d in data8]
da = [d1,d2,d3,d4,d5,d6]
for x in zip(*da):
y = list(x)
a1 = y[0]
a2 = y[1]
a3 = y[2]
a4 = y[3]
a5 = y[4]
a6 = y[5]
b1 = np.array(a1)
b2 = np.array(a2)
b3 = np.array(a3)
b4 = np.array(a4)
b5 = np.array(a5)
b6 = np.array(a6)
c1 = b2.tolist()
c2 = b4.tolist()
c4 = b6.tolist()
print(type(c1))
当我使用print（list（c1））
时shell告诉我
['[', '[', '0', ',', ' ', '4', '5', ']', ',', ' ', '[', '0', ',', ' ', '-', '4', '5', ',', ' ', '4', '5', ']', ',', ' ', '[', '0', ',', ' ', '-', '4', '5', ',', ' ', '4', '5', ',', ' ', '-', '2', '6', ']', ']']
我只想要[[0, 45], [0, -45, 45], [0, -45, 45, -26]]这样，类型必须是列表
答案 0 :(得分：1)
我只想这样
[[0, 45], [0, -45, 45], [0, -45, 45, -26]]类型必须是列表
我对你的代码看起来有多复杂感到有点震惊，所以我做的第一件事就是查看输入数据，如下所示：
[
{
"id":"1",
"array1_1":"0",
"array1_2":"1",
"array2_1":"2",
"array2_2":"3",
"array3_1":"44",
"array3_2":"55"
},
{
"id":"asd",
"array1_1":"234",
"array1_2":"[[0, 26, 60, 45], [0, -45, 45]]",
"array2_1":"[[23, 345], [543, 321]]",
"array2_2":"jytj",
"array3_1":"5",
"array3_2":"6"
},
{
"id":"bb",
"array1_1":"bbb",
"array1_2":"ad",
"array2_1":"[[23, 345], [543, 321]]",
"array2_2":"[[0, 45], [45]]",
"array3_1":"[[34, 45], [66, 88]]",
"array3_2":"sfw"
},
{
"id":"aa",
"array1_1":"aa",
"array1_2":"[[0, 26, 60, 45], [0, -45, 45]]",
"array2_1":"gfd",
"array2_2":"[[0, 45], [45]]",
"array3_1":"sdf",
"array3_2":"[[26, 60], [0], [56, 34, 45]]"
},
{
"id":"ss",
"array1_1":"00",
"array1_2":"[[0, 45], [0, -45, 45], [0, -45, 45, -26]]",
"array2_1":"[[31, 233], [152, 151], [190, 204], [205, 87], [231, 48], [255, 194]]",
"array2_2":"[[0, 45], [45], [45], [26, 45, 63], [45], [0, 26, 45, 63]]",
"array3_1":"[[29, 194], [32, 234], [165, 229], [232, 46], [258, 190]]",
"array3_2":"[[45], [0, 45], [0, 26, 45], [0, -63, 45, 63], [0, 26, 45]]"
}
]
以下观察：
bytes b''，却是string list dictionaries的完美“id:'ss' array1_2和eval()值使用decode()，您可以在# no imports needed
def get_my_values(data: bytes,
key: str,
key_v: str,
req: str,
codec: str = 'utf-8') -> str:
'''
data = bytes representing a string representing a list of dictionaries
key = key to use to select the element/dictionary of the list
key_v = value to match for the key to select the element/dictionary
req = required key of the dictionary to return its values
codec = codec to use for decode(), defaults to 'utf-8' when omitted
'''
l = eval(data.decode(codec)) ## decode and make a list
for d in l: ## enumerate through list to get dictionary
if d[key] == key_v: ## only if key is the required, matching value
return d[req] ## return the values required
if __name__ == '__main__':
# input data
data = b'[{"id":"1","array1_1":"0","array1_2":"1","array2_1":"2","array2_2":"3","array3_1":"44","array3_2":"55"},{"id":"asd","array1_1":"234","array1_2":"[[0, 26, 60, 45], [0, -45, 45]]","array2_1":"[[23, 345], [543, 321]]","array2_2":"jytj","array3_1":"5","array3_2":"6"},{"id":"bb","array1_1":"bbb","array1_2":"ad","array2_1":"[[23, 345], [543, 321]]","array2_2":"[[0, 45], [45]]","array3_1":"[[34, 45], [66, 88]]","array3_2":"sfw"},{"id":"aa","array1_1":"aa","array1_2":"[[0, 26, 60, 45], [0, -45, 45]]","array2_1":"gfd","array2_2":"[[0, 45], [45]]","array3_1":"sdf","array3_2":"[[26, 60], [0], [56, 34, 45]]"},{"id":"ss","array1_1":"00","array1_2":"[[0, 45], [0, -45, 45], [0, -45, 45, -26]]","array2_1":"[[31, 233], [152, 151], [190, 204], [205, 87], [231, 48], [255, 194]]","array2_2":"[[0, 45], [45], [45], [26, 45, 63], [45], [0, 26, 45, 63]]","array3_1":"[[29, 194], [32, 234], [165, 229], [232, 46], [258, 190]]","array3_2":"[[45], [0, 45], [0, 26, 45], [0, -63, 45, 63], [0, 26, 45]]"}]'
# selection criteria
selection_key = 'id' ## this is the key to use for selection of the list element
selection_value = 'ss' ## this is the value of the selection key
required_key = 'array1_2' ## this is the key you want values returned
# get required values from data
result = get_my_values(data, selection_key, selection_value, required_key) ## get values
# make a list if possible
try:
result = eval(result) ## make it a list if possible
except NameError:
pass ## cannot be made a list, and is a single value
# print results
print(result)
print(type(result))
这是一个例子：
[[0, 45], [0, -45, 45], [0, -45, 45, -26]]
<class 'list'>
示例输出：
selectizeInput答案 1 :(得分：0)
改为使用print(c1)。
c1已经是一个列表，因此print(list(c1))会重新列出它。