我有以下数据结构,我正在寻求转换。结构如下:
{
"id": "13fd6574-dc33-4b8c-a09b-a937869d184f",
"practiceId": 2,
"extrasCoverServices": [
{
"serviceTypeName": "OCCUPATIONAL THERAPY",
"serviceTypeCode": "H",
"providers": [
{
"providerNumber": "157833AC",
"providerName": "DR TEST"
}
],
"serviceItems": [
{
"itemName": "INITIAL CONS",
"itemNumber": "100",
"fee": 0,
"isReferenceItem": "true",
"customisations": [
{
"practiceDisplayName": "First Assessment",
"fee": 50,
"isPracticeReferenceItem": "true"
}
]
},
{
"itemName": "CONS TREAT",
"itemNumber": "200",
"fee": 0,
"isReferenceItem": "true",
"customisations": [
{
"practiceDisplayName": "Consult One",
"fee": 23.35,
"isPracticeReferenceItem": "true"
},
{
"practiceDisplayName": "Consult Two",
"fee": 15,
"isPracticeReferenceItem": "false"
}
]
}
]
}
]
}
我想要一个返回id,practiceId和extrasCoverservices(serviceTypeName,serviceTypeCode和serviceItems)的查询。我不想包含提供商信息。
我试过这个,但我需要在数组中指定元素的位置,我不想这样做。任何帮助将不胜感激。
SELECT a.id
, a.practiceId
, [{"serviceTypeName": a.extrasCoverServices[0].serviceTypeName, "serviceTypeCode": a.extrasCoverServices[0].serviceTypeCode, "serviceItems": a.extrasCoverServices[0].serviceItems}]
更新
function sample(documentId) {
var collection = getContext().getCollection();
var isAccepted = collection.queryDocuments(
collection.getSelfLink(),
'SELECT ARRAY_CONCAT([{"itemId": s.itemId, "itemName": s.itemName,"itemNumber":s.itemNumber,"fee":s.fee,"isReferenceItem":s.isReferenceItem}], IS_DEFINED(s.customisations) ? s.customisations : []) as extrasCoverServices FROM a JOIN e in a.extrasCoverServices JOIN s in e.serviceItems WHERE a.id =' + "'" + documentId + "'",
function (err, feed, options) {
if (err) throw err;
if (!feed || !feed.length) getContext().getResponse().setBody('no docs found');
else {
console.log(feed.length);
var result = feed.flatten(function(x) {
return x.extrasCoverServices;
});
getContext().getResponse().setBody(result);
}
});
if (!isAccepted) throw new Error('The query was not accepted by the server.');
}
答案 0 :(得分:0)
请使用sql:
SELECT a.id,a.practiceId,e.serviceTypeName,e.serviceTypeCode,e.serviceItems
FROM a
join e in a.extrasCoverServices a
结果:
如果您想将e.serviceTypeName,e.serviceTypeCode,e.serviceItems
放入数组中,而不是与id
和praticeId
并行,我建议您在cosmos db中使用存储过程。
function sample() {
var collection = getContext().getCollection();
var isAccepted = collection.queryDocuments(
collection.getSelfLink(),
'SELECT c.id,c.practiceId,c.extrasCoverServices FROM root c',
function (err, feed, options) {
if (err) throw err;
if (!feed || !feed.length) getContext().getResponse().setBody('no docs found');
else {
var returnResult = [];
for(var i = 0;i<feed.length;i++){
var obj1 = {
id:"",
practiceId:"",
serviceArray :[]
};
obj1.id = feed[i].id;
obj1.practiceId = feed[i].practiceId;
var loopArray = feed[i].extrasCoverServices;
var serviceResult = [];
for(var j = 0;j<loopArray.length;j++){
var obj2 = {
serviceTypeName:"",
serviceTypeCode:"",
serviceItems:[] };
obj2.serviceTypeName=loopArray[j].serviceTypeName;
obj2.serviceTypeCode=loopArray[j].serviceTypeCode;
obj2.serviceItems=loopArray[j].serviceItems;
serviceResult.push(obj2);
}
obj1.serviceArray= serviceResult;
returnResult.push(obj1);
}
getContext().getResponse().setBody(returnResult);
}
});
if (!isAccepted) throw new Error('The query was not accepted by the server.');
}
结果:
希望它对你有所帮助。
更新答案1:
为了您的评论中的进一步要求,我为您测试了一个SQL。
SELECT
a.id,
a.practiceId,
[{
"serviceTypeName": e.serviceTypeName,
"serviceTypeCode" : e.serviceTypeCode,
"serviceItems": [
{"itemName": s.itemName,
"itemNumber":s.itemNumber,
"fee":s.fee,
"isReferenceItem":s.isReferenceItem
},
{"practiceDisplayName":c.practiceDisplayName,
"itemNumber":s.itemNumber,
"fee": c.fee,
"isPracticeReferenceItem":c.isPracticeReferenceItem
}
]
}] as extrasCoverServices
FROM a
join e in a.extrasCoverServices
join s in e.serviceItems
join c in s.customisations
但是,由于join
。
[
{
"id": "13fd6574-dc33-4b8c-a09b-a937869d184f",
"practiceId": 2,
"extrasCoverServices": [
{
"serviceTypeName": "OCCUPATIONAL THERAPY",
"serviceTypeCode": "H",
"serviceItems": [
{
"itemName": "INITIAL CONS",
"itemNumber": "100",
"fee": 0,
"isReferenceItem": "true"
},
{
"practiceDisplayName": "First Assessment",
"itemNumber": "100",
"fee": 50,
"isPracticeReferenceItem": "true"
}
]
}
]
},
{
"id": "13fd6574-dc33-4b8c-a09b-a937869d184f",
"practiceId": 2,
"extrasCoverServices": [
{
"serviceTypeName": "OCCUPATIONAL THERAPY",
"serviceTypeCode": "H",
"serviceItems": [
{
"itemName": "CONS TREAT",
"itemNumber": "200",
"fee": 0,
"isReferenceItem": "true"
},
{
"practiceDisplayName": "Consult One",
"itemNumber": "200",
"fee": 23.35,
"isPracticeReferenceItem": "true"
}
]
}
]
},
{
"id": "13fd6574-dc33-4b8c-a09b-a937869d184f",
"practiceId": 2,
"extrasCoverServices": [
{
"serviceTypeName": "OCCUPATIONAL THERAPY",
"serviceTypeCode": "H",
"serviceItems": [
{
"itemName": "CONS TREAT",
"itemNumber": "200",
"fee": 0,
"isReferenceItem": "true"
},
{
"practiceDisplayName": "Consult Two",
"itemNumber": "200",
"fee": 15,
"isPracticeReferenceItem": "false"
}
]
}
]
}
]
因此,我建议您在存储过程中处理结果以符合您的要求。
function sample() {
var collection = getContext().getCollection();
var isAccepted = collection.queryDocuments(
collection.getSelfLink(),
'SELECT a.id, a.practiceId,'+
'[{'+
'"serviceTypeName": e.serviceTypeName, '+
'"serviceTypeCode" : e.serviceTypeCode, '+
'"serviceItems": ['+
'{"itemName": s.itemName,'+
'"itemNumber":s.itemNumber,'+
'"fee":s.fee,'+
'"isReferenceItem":s.isReferenceItem'+
'},'+
'{"practiceDisplayName":c.practiceDisplayName,'+
'"itemNumber":s.itemNumber,'+
'"fee": c.fee,'+
'"isPracticeReferenceItem":c.isPracticeReferenceItem '+
'}'+
']'+
'}] as extrasCoverServices'+
' FROM a '+
' join e in a.extrasCoverServices'+
' join s in e.serviceItems'+
' join c in s.customisations',
function (err, feed, options) {
if (err) throw err;
if (!feed || !feed.length) getContext().getResponse().setBody('no docs found');
else {
var returnResult = [];
var obj1 = {
id:"",
practiceId:"",
extrasCoverServices :[]
};
var temp = "";
for(var i = 0;i<feed.length;i++){
if(temp==feed[i].id){
var extrasArray = obj1.extrasCoverServices[0].serviceItems;
var serviceArray = feed[i].extrasCoverServices[0].serviceItems;
for(var j = 0;j<serviceArray.length;j++){
extrasArray.push(serviceArray[j]);
}
obj1.extrasCoverServices[0].serviceItems = extrasArray;
} else{
obj1.id = feed[i].id;
obj1.practiceId = feed[i].practiceId;
obj1.extrasCoverServices = feed[i].extrasCoverServices;
temp = feed[i].id;
}
}
returnResult.push(obj1);
getContext().getResponse().setBody(returnResult);
}
});
if (!isAccepted) throw new Error('The query was not accepted by the server.');
}
处理结果:
[
{
"id": "13fd6574-dc33-4b8c-a09b-a937869d184f",
"practiceId": 2,
"extrasCoverServices": [
{
"serviceTypeName": "OCCUPATIONAL THERAPY",
"serviceTypeCode": "H",
"serviceItems": [
{
"itemName": "INITIAL CONS",
"itemNumber": "100",
"fee": 0,
"isReferenceItem": "true"
},
{
"practiceDisplayName": "First Assessment",
"itemNumber": "100",
"fee": 50,
"isPracticeReferenceItem": "true"
},
{
"itemName": "CONS TREAT",
"itemNumber": "200",
"fee": 0,
"isReferenceItem": "true"
},
{
"practiceDisplayName": "Consult One",
"itemNumber": "200",
"fee": 23.35,
"isPracticeReferenceItem": "true"
},
{
"itemName": "CONS TREAT",
"itemNumber": "200",
"fee": 0,
"isReferenceItem": "true"
},
{
"practiceDisplayName": "Consult Two",
"itemNumber": "200",
"fee": 15,
"isPracticeReferenceItem": "false"
}
]
}
]
}
]
更新答案2:
好吧,我仍然专注于通过存储过程实现您的需求。
我将一个没有customisations
数组的项目添加到serviceItems
中,如下所示:
[
{
"id": "13fd6574-dc33-4b8c-a09b-a937869d184f",
"practiceId": 2,
"extrasCoverServices": [
{
"serviceTypeName": "OCCUPATIONAL THERAPY",
"serviceTypeCode": "H",
"serviceItems": [
{
"itemName": "INITIAL CONS",
"itemNumber": "100",
"fee": 0,
"isReferenceItem": "true",
"customisations": [
{
"practiceDisplayName": "First Assessment",
"fee": 50,
"isPracticeReferenceItem": "true"
}
]
},
{
"itemName": "CONS TREAT",
"itemNumber": "200",
"fee": 0,
"isReferenceItem": "true",
"customisations": [
{
"practiceDisplayName": "Consult One",
"fee": 23.35,
"isPracticeReferenceItem": "true"
},
{
"practiceDisplayName": "Consult Two",
"fee": 15,
"isPracticeReferenceItem": "false"
}
]
},
{
"itemName": "FOR TEST",
"itemNumber": "333",
"fee": 20,
"isReferenceItem": "true"
}
]
}
]
}
]
SP代码:
function sample() {
var collection = getContext().getCollection();
var isAccepted = collection.queryDocuments(
collection.getSelfLink(),
'SELECT a.id, a.practiceId,'+
'[{'+
'"serviceTypeName": e.serviceTypeName, '+
'"serviceTypeCode" : e.serviceTypeCode, '+
'"serviceItems": e.serviceItems'+
'}] as extrasCoverServices'+
' FROM a '+
' join e in a.extrasCoverServices',
function (err, feed, options) {
if (err) throw err;
if (!feed || !feed.length) getContext().getResponse().setBody('no docs found');
else {
for(var i = 0;i<feed.length;i++){
var extraArray = feed[i].extrasCoverServices;
for(var j = 0;j<extraArray.length;j++){
var serviceArray = extraArray[j].serviceItems;
var array = [];
for(var k = 0;k<serviceArray.length;k++){
var o1 = {
"itemName": "",
"itemNumber":"",
"fee" : "",
"isReferenceItem":""
};
console.log(k+"----");
o1.itemName = serviceArray[k].itemName;
o1.itemNumber = serviceArray[k].itemNumber;
o1.fee = serviceArray[k].fee;
o1.isReferenceItem = serviceArray[k].isReferenceItem;
console.log(o1.itemName);
array.push(o1);
if(null != serviceArray[k].customisations){
var customisationsArray = serviceArray[k].customisations;
for(var p = 0;p<customisationsArray.length;p++){
var o2 = {
"practiceDisplayName": "",
"itemNumber":"",
"fee" : "",
"isPracticeReferenceItem":""
};
o2.practiceDisplayName = customisationsArray[p].practiceDisplayName;
o2.itemNumber = o1.itemNumber;
o2.fee = customisationsArray[p].fee;
o2.isPracticeReferenceItem = customisationsArray[p].isPracticeReferenceItem;
array.push(o2);
}
}
}
feed[i].extrasCoverServices[j].serviceItems = array;
}
}
getContext().getResponse().setBody(feed);
}
});
if (!isAccepted) throw new Error('The query was not accepted by the server.');
}
为了总结,我整理了你最后的SP代码。这是一个很好的主题。
function sample(documentId, itemId) {
var collection = getContext().getCollection();
var query = 'SELECT e.serviceTypeCode, '+
' e.serviceTypeName, '+
' s.itemNumber, '+
' ARRAY_CONCAT( '+
' [{ '+
' "itemId": s.itemId, '+
' "itemName": s.itemName, '+
' "fee":s.fee, '+
' "isReferenceItem":s.isReferenceItem '+
' }], '+
' IS_DEFINED(s.customisations) ? s.customisations : []) as extrasCoverServices '+
' FROM a '+
' JOIN e in a.extrasCoverServices '+
' JOIN s in e.serviceItems '+
' WHERE a.id = ' + "'" + documentId + "'";
var isAccepted = collection.queryDocuments(
collection.getSelfLink(),
query,
function (err, feed, options) {
if (err) throw err;
if (!feed || !feed.length) getContext().getResponse().setBody('no docs found');
var returnResult = [];
for(var i = 0; i<feed.length; i++) {
let serviceItem = feed[i];
let serviceItemsArray = feed[i].extrasCoverServices;
for(var j = 0; j < serviceItemsArray.length; j++) {
let item = serviceItemsArray[j];
let mapped = {
serviceTypeCode: serviceItem.serviceTypeCode
, serviceTypeName: serviceItem.serviceTypeName
, itemId: item.itemId
, itemName: (item.itemName ? item.itemName : item.practiceDisplayName)
, itemNumber: serviceItem.itemNumber
, fee: item.fee
, isReferenceItem: ((item.isReferenceItem && item.isReferenceItem == true) ? item.isReferenceItem: false)
, isPracticeReferenceItem: (item.isPracticeReferenceItem && item.isPracticeReferenceItem == true ? item.isPracticeReferenceItem : false)
};
returnResult.push(mapped);
}
}
if(itemId != undefined) {
var filteredReturnResult = returnResult.filter(r => r.itemId == itemId);
getContext().getResponse().setBody(filteredReturnResult);
return
}
getContext().getResponse().setBody(returnResult);
if (!isAccepted) throw new Error('The query was not accepted by the server.');
})
}
答案 1 :(得分:0)
你几乎拥有它。为此,您可以使用以下功能:
join
关键字{
和}
包装器第一个允许您访问要挑选的子项目,第二个允许您按照自己喜欢的方式将它们粘合在一起。
您正在寻找的查询应该是这样的:
SELECT
a.id,
a.practiceId,
[{
"serviceTypeName": e.serviceTypeName,
"serviceTypeCode" : e.serviceTypeCode,
"serviceItems": e.serviceItems
}] as extrasCoverServices
FROM a
join e in a.extrasCoverServices
请注意,您可以在同一查询中将类似Sql的select与显式JSON构建相结合,以使查询更紧凑。另外,我建议您使用CosmosDB SQL query cheat sheet轻松发现工具箱中的内容。
答案 2 :(得分:0)
function sample(documentId, itemId) {
var collection = getContext().getCollection();
var query = 'SELECT e.serviceTypeCode, '+
' e.serviceTypeName, '+
' s.itemNumber, '+
' ARRAY_CONCAT( '+
' [{ '+
' "itemId": s.itemId, '+
' "itemName": s.itemName, '+
' "fee":s.fee, '+
' "isReferenceItem":s.isReferenceItem '+
' }], '+
' IS_DEFINED(s.customisations) ? s.customisations : []) as extrasCoverServices '+
' FROM a '+
' JOIN e in a.extrasCoverServices '+
' JOIN s in e.serviceItems '+
' WHERE a.id = ' + "'" + documentId + "'";
var isAccepted = collection.queryDocuments(
collection.getSelfLink(),
query,
function (err, feed, options) {
if (err) throw err;
if (!feed || !feed.length) getContext().getResponse().setBody('no docs found');
var returnResult = [];
for(var i = 0; i<feed.length; i++) {
let serviceItem = feed[i];
let serviceItemsArray = feed[i].extrasCoverServices;
for(var j = 0; j < serviceItemsArray.length; j++) {
let item = serviceItemsArray[j];
let mapped = {
serviceTypeCode: serviceItem.serviceTypeCode
, serviceTypeName: serviceItem.serviceTypeName
, itemId: item.itemId
, itemName: (item.itemName ? item.itemName : item.practiceDisplayName)
, itemNumber: serviceItem.itemNumber
, fee: item.fee
, isReferenceItem: ((item.isReferenceItem && item.isReferenceItem == true) ? item.isReferenceItem: false)
, isPracticeReferenceItem: (item.isPracticeReferenceItem && item.isPracticeReferenceItem == true ? item.isPracticeReferenceItem : false)
};
returnResult.push(mapped);
}
}
if(itemId != undefined) {
var filteredReturnResult = returnResult.filter(r => r.itemId == itemId);
getContext().getResponse().setBody(filteredReturnResult);
return
}
getContext().getResponse().setBody(returnResult);
if (!isAccepted) throw new Error('The query was not accepted by the server.');
})
}