Question

我试图找出工作人员刚开始时的工资，为了做到这一点，我使用了一个连接功能，将一个表（EMPOS aka POSI）中的员工开始日期与员工的起薪日期相匹配。另一个表（EMSAL又称SAL），用于检索开始角色之日的工资金额。我想使用MIN函数来从EMPOS aka POSI中选择最低日期（开始日期），以及该日期是否与EMSAL aka SAL表中的工资日期和金额日期相匹配。

我遇到了以下错误

聚合不能出现在ON子句中，除非它位于HAVING子句或选择列表中包含的子查询中，并且列中   被聚合是一个外部参考。

这是我的代码汇总 -

Select CS.Name, SAL.SalaryAmount 
FROM CurrentStaff as CS

LEFT OUTER JOIN EMPOS as POSI ON CS.DET_NUMBERA = POSI.DET_NUMBER COLLATE 
SQL_Latin1_General_CP1_CI_AS AND CS.POS_STARTC = POSI.POS_START

LEFT OUTER JOIN EMSAL SAL on CS.DET_NUMBERA = SAL.DET_NUMBER COLLATE 
SQL_Latin1_General_CP1_CI_AS AND SAL.SMN_DATE 
= (SELECT MIN(POSI.POS_START) FROM EMPOS)

非常感谢您的协助。如果您有任何疑问或需要进一步的信息，请告诉我:)）

干杯！

Answer 1

一种方法是使用子查询替换您对EMPOS表的连接，该子查询查找每个员工的早期日期。然后，使用该子查询限制到每个员工的第一条记录。

SELECT
    CS.Name, SAL.SalaryAmount
FROM CurrentStaff AS CS
LEFT JOIN
(
    SELECT DET_NUMBER, MIN(POS_START) AS first_start
    FROM EMPOS
    GROUP BY DET_NUMBER
) POSI
    ON CS.DET_NUMBERA = POSI.DET_NUMBER COLLATE
        SQL_Latin1_General_CP1_CI_AS AND CS.POS_STARTC = POSI.POS_START
LEFT JOIN EMSAL SAL
    ON CS.DET_NUMBERA = SAL.DET_NUMBER AND
       SAL.SMN_DATE = POSI.first_start COLLATE 
        SQL_Latin1_General_CP1_CI_AS;

Answer 2

Select CS.Name, SAL.SalaryAmount 
FROM CurrentStaff as CS

LEFT OUTER JOIN EMPOS as POSI ON CS.DET_NUMBERA = POSI.DET_NUMBER COLLATE 
SQL_Latin1_General_CP1_CI_AS AND CS.POS_STARTC = POSI.POS_START

LEFT OUTER JOIN 
    (SELECT * 
     FROM EMSAL 
     WHERE SMN_DATE = (SELECT MIN(POS_START) 
                       FROM EMPOS)
    ) SAL 
on CS.DET_NUMBERA = SAL.DET_NUMBER COLLATE SQL_Latin1_General_CP1_CI_AS

Answer 3

子查询中有错误的表别名：

SELECT CS.Name, SAL.SalaryAmount 
FROM CurrentStaff CS LEFT OUTER JOIN
     EMPOS POSI
     ON CS.DET_NUMBERA = POSI.DET_NUMBER COLLATE 
 SQL_Latin1_General_CP1_CI_AS AND 
        CS.POS_STARTC = POSI.POS_START LEFT OUTER JOIN
     EMSAL SAL 
     ON CS.DET_NUMBERA = SAL.DET_NUMBER COLLATE 
SQL_Latin1_General_CP1_CI_AS AND 
        SAL.SMN_DATE = (SELECT MIN(POSI2.POS_START) FROM EMPOS POSI2);

但是，我发现subqueries in the ON`条款难以理解，所以我将其写成：

SELECT CS.Name, SAL.SalaryAmount 
FROM CurrentStaff CS LEFT OUTER JOIN
     (SELECT POSI.*, MIN(POSI.POS_START) OVER () as MIN_POS_START
      FROM EMPOS POSI
     ) POSI
     ON CS.DET_NUMBERA = POSI.DET_NUMBER COLLATE 
 SQL_Latin1_General_CP1_CI_AS AND 
        CS.POS_STARTC = POSI.POS_START LEFT OUTER JOIN
     EMSAL SAL 
     ON CS.DET_NUMBERA = SAL.DET_NUMBER COLLATE 
SQL_Latin1_General_CP1_CI_AS AND 
        SAL.SMN_DATE = POSI.MIN_POS_START) ;

那就是说，我也很惊讶你希望整体最低，而不是每个员工的最低要求。所以，MIN()应该是：

MIN(POSI.POS_START) OVER (PARTITION BY POSI.DET_NUMBER)

同样，您的子查询应该有一个关联子句。

连接子句的聚合错误（选择MIN日期）

3 个答案: