Question

我正在尝试在python中对字典进行排序，如下所示：在这种情况下，我的词典有“ESPN”，“AAA”是键，值在

之下

'ESPN': [
    'ESPN 90 TO 100_1050',
    'ESPN 60 TO 70_1150',
    'ESPN 80 TO 90_1250',
    'ESPN 90 TO 100_1750',
    'ESPN 90 TO 100_900'
    'ESPN 90 TO 100_1650',
    'ESPN 70 TO 80_1350',
    'ESPN 20 TO 30_1450'
]

'AAA': [
    'AAA 90 TO 100_1050',
    'AAA 60 TO 70_1150',
    'AAA 80 TO 90_1250',
    'AAA 90 TO 100_1750',
    'AAA 90 TO 100_1650',
    'AAA 70 TO 80_1350',
    'AAA 20 TO 30_1450'
]

我试图按照这样的方式对这个词典进行排序，以便我希望ESPN和AAA之后的数字以递增的方式以及下划线之后的数字。

例如如下

'ESPN': [
    'ESPN 20 TO 30_1450',
    'ESPN 60 TO 70_1150',
    'ESPN 70 TO 80_1350',
    'ESPN 80 TO 90_1250',
    'ESPN 90 TO 100_900',
    'ESPN 90 TO 100_1650',
    'ESPN 90 TO 100_1750',
]

我正在尝试正则表达式并排序，但我无法得到它。如果有人能提供帮助，真的很感激。我也尝试了各种排序技术，但我总是最终排序键而不是值。此外，在大多数情况下，它没有按预期工作，因为当我的值为AAA 20到30_900时，它在AAA 20到30_1450之前没有按顺序排列，而是在它之后。

TIA

Answer 1

这是使用连续str.split次呼叫的一种方式。映射到整数可确保900在1000之前出现。

def sorter(x):
    _, var1, _, var2 = x.split()
    var2a, var2b = var2.split('_')
    return list(map(int, (var1, var2a, var2b)))

res = sorted(d['ESPN'], key=sorter)

['ESPN 20 TO 30_1450',
 'ESPN 60 TO 70_1150',
 'ESPN 70 TO 80_1350',
 'ESPN 80 TO 90_1250',
 'ESPN 90 TO 100_900',
 'ESPN 90 TO 100_1050',
 'ESPN 90 TO 100_1650',
 'ESPN 90 TO 100_1750']

Answer 2

d = {
    'ESPN': [
        'ESPN 90 TO 100_1050',
        'ESPN 60 TO 70_1150',
        'ESPN 80 TO 90_1250',
        'ESPN 90 TO 100_1750',
        'ESPN 90 TO 100_1650',
        'ESPN 70 TO 80_1350',
        'ESPN 20 TO 30_1450'
    ],
    'AAA': [
        'AAA 90 TO 100_1050',
        'AAA 60 TO 70_1150',
        'AAA 80 TO 90_1250',
        'AAA 90 TO 100_1750',
        'AAA 90 TO 100_1650',
        'AAA 70 TO 80_1350',
        'AAA 20 TO 30_1450'
    ]
}
[v.sort() for v in d.values()]

结果：

{'AAA': ['AAA 20 TO 30_1450',
  'AAA 60 TO 70_1150',
  'AAA 70 TO 80_1350',
  'AAA 80 TO 90_1250',
  'AAA 90 TO 100_1050',
  'AAA 90 TO 100_1650',
  'AAA 90 TO 100_1750'],
 'ESPN': ['ESPN 20 TO 30_1450',
  'ESPN 60 TO 70_1150',
  'ESPN 70 TO 80_1350',
  'ESPN 80 TO 90_1250',
  'ESPN 90 TO 100_1050',
  'ESPN 90 TO 100_1650',
  'ESPN 90 TO 100_1750']}

Answer 3

您可以使用re.findall提取所有连续的数字序列，转换为整数并应用字典排序。

key = lambda s: tuple(map(int, re.findall('\d+', s)))
result = {k: sorted(v, key=key) for k, v in data.items()}

# Output

In [156]: result
Out[156]: 
{'AAA': ['AAA 20 TO 30_1450',
  'AAA 60 TO 70_1150',
  'AAA 70 TO 80_1350',
  'AAA 80 TO 90_1250',
  'AAA 90 TO 100_1050',
  'AAA 90 TO 100_1650',
  'AAA 90 TO 100_1750'],
 'ESPN': ['ESPN 20 TO 30_1450',
  'ESPN 60 TO 70_1150',
  'ESPN 70 TO 80_1350',
  'ESPN 80 TO 90_1250',
  'ESPN 90 TO 100_900',
  'ESPN 90 TO 100_1050',
  'ESPN 90 TO 100_1650',
  'ESPN 90 TO 100_1750']}

在python中对字典的字母数字值进行排序

3 个答案: